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sergij07 [2.7K]
1 year ago
10

PLEASE ANSWER THIS!!!!!!!!

Mathematics
1 answer:
sergiy2304 [10]1 year ago
3 0

9514 1404 393

Answer:

  (a)  x - y + 1 = 0

Step-by-step explanation:

One way to address multiple-choice questions is to try the answers to see what works.

For the lower left point (1, 2), the answer choices shown give ...

  x -y +1 = 1 -2 +1 = 0 . . . . . equation works

  -x -y +1 = -1 -2 +1 = -2 . . . doesn't work

  y -x +1 = 2 -1 +1 = 2 . . . . . doesn't work

The appropriate choice is ...

  x - y + 1 = 0

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A solid machine part is to be manufactured as shown in the figure. The part is made by cutting a small cone off the top of a lar
Alexxx [7]

Answer:

The answer is 390 × pi.

Step-by-step explanation:

Big cone:

V = 1/3 x pi x r^2 x h

= 1/3 x 3.14 x 9^2 x 15

= 1272.3 cubic inches

Small cone:

V = 1/3 x pi x r^2 x h

= 1/3 x 3.14 x 3^2 x 5

= 47.1 cubic inches  

1272.3 - 47.1 = 1225.2 cubic inches

1272/3.14 ≈ 390

The answer is 390 × pi.

4 0
1 year ago
Tiffany buys a basket of watermelons on sale for \$9$9dollar sign, 9 before tax. The sales tax is 9\%9%9, percent. What is the t
vladimir2022 [97]
Given that the basket of watermelons sells for $9 before tax and the tax rate is 9%.

The tax on the basket of watermelons is given by

\frac{9\%}{100\%} \times\$9=0.09\times\$9 \\  \\ =\$0.81

Therefore, the total price Tiffany pays for the basket of watermelons is $9 + $0.81 = $9.81
8 0
2 years ago
Read 3 more answers
What is the result of anding 255 and 15?
Tema [17]
The result of adding 255 and 15 is;

255 + 15 = 270


8 0
1 year ago
ANSWER ALL 5 PARTS.
N76 [4]
A function f from a set A to a set B is defined as a relation that assings to each element  x in the set A exactly one element y in the set B. The set A is called the domain of the function while the set B is the range. So we have five statements and need to find some functions. Melissa decides to reserve a patch in her vegetable garden for growing bell peppers. If each side of the tomato patch is x feet, then we have a square patch as shown in the Figure below.

1.a) Write the function Wa(x) representing the width of the bell pepper patch.

We know that she wants its width to be half the width of the tomato patch. Let x be the width of the tomato patch, then the function that matches this statement is:

\boxed{Wa(x)=\frac{x}{2}}

1.b) Write the function La(x) representing the length of the bell pepper patch.

In this case Melissa wants <span>its length to exceed the length of the tomato patch by 2 feet. To do this we enlarge the length of the tomato patch 2 feet. Therefore the function is the following:

</span>\boxed{La(x)=x+2}
<span>
2. Ar</span>ea of the bell pepper patch in terms of x.

Given that the bell pepper patch is a rectangle, then t<span>he area of a rectangle is the product of the length and width. So:

</span>A=(\frac{x}{2})(x+2) \\ \\ \therefore \boxed{A=\frac{x(x+2)}{2}}
<span>
3. C</span><span>ombined area of the tomato patch and the bell pepper patch.

This function is the sum of both the area of the tomato patch and the bell pepper patch. So:

</span>Aar(x)=x^{2}+\frac{x(x+2)}{2} \rightarrow Aar(x)=x^{2}+ \frac{x^{2}}{2}+x \rightarrow Aar(x)=\frac{3x^{2}}{2}+x \\ \\ \therefore \boxed{Aar(x)=\frac{x(3x+2)}{2}}
<span>
4. W</span>rite the function Aa(x) for the remaining planting area in the garden.

The remaining planting area in the garden are the rectangles in red. So we need to subtract the width of the bell pepper patch from the width of the tomato patch and multiply it by 2. In mathematical language this is given by:<span>

</span>Aa(x)=2(x-\frac{x}{2}) \rightarrow Aa(x)=x

5. 
Find the area of the remaining space in the garden after planting tomatoes and bell peppers.

Given that <span>Melissa wants the area of the bell pepper patch to be 31.5 square feet, then it is true that:

</span>31.5=\frac{x(x+2)}{2} \rightarrow x^{2}+2x-64=0 \\ \\ solving \ for \ x: \\ x=7.06
<span>
Therefore the area of the remaining space is:

</span>\boxed{Aa(7.06)=7.06ft^{2}}

6 0
2 years ago
A circle with radius of \greenD{4\,\text{cm}}4cmstart color #1fab54, 4, start text, c, m, end text, end color #1fab54 sits insid
mario62 [17]

Answer:

The area of the shaded region is   329.87\ cm^2

Step-by-step explanation:

<u><em>The correct question is</em></u>

A circle with radius of 4cm sits inside a circle with a radius of 11cm. What is the area of the shaded region?

The shaded region is the area outside the smaller circle and inside the larger circle

we know that

To find out the shaded region subtract the area of the smaller circle from the area of the larger circle

so

A=\pi r_a^{2} -\pi r_b^{2}

simplify

A=\pi (r_a^{2} -r_b^{2})

where

r_a is the radius of the larger circle

r_b is the radius of the smaller circle

we have

r_a=11\ cm\\r_b=4\ cm

substitute

A=\pi (11^{2} -4^{2})

A=\pi (105)\ cm^2

assume

\pi=3.1416

substitute

A=(3.1416)(105)=329.87\ cm^2

7 0
2 years ago
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