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Misha Larkins [42]
2 years ago
7

ANSWER ALL 5 PARTS.

Mathematics
1 answer:
N76 [4]2 years ago
6 0
A function f from a set A to a set B is defined as a relation that assings to each element  x in the set A exactly one element y in the set B. The set A is called the domain of the function while the set B is the range. So we have five statements and need to find some functions. Melissa decides to reserve a patch in her vegetable garden for growing bell peppers. If each side of the tomato patch is x feet, then we have a square patch as shown in the Figure below.

1.a) Write the function Wa(x) representing the width of the bell pepper patch.

We know that she wants its width to be half the width of the tomato patch. Let x be the width of the tomato patch, then the function that matches this statement is:

\boxed{Wa(x)=\frac{x}{2}}

1.b) Write the function La(x) representing the length of the bell pepper patch.

In this case Melissa wants <span>its length to exceed the length of the tomato patch by 2 feet. To do this we enlarge the length of the tomato patch 2 feet. Therefore the function is the following:

</span>\boxed{La(x)=x+2}
<span>
2. Ar</span>ea of the bell pepper patch in terms of x.

Given that the bell pepper patch is a rectangle, then t<span>he area of a rectangle is the product of the length and width. So:

</span>A=(\frac{x}{2})(x+2) \\ \\ \therefore \boxed{A=\frac{x(x+2)}{2}}
<span>
3. C</span><span>ombined area of the tomato patch and the bell pepper patch.

This function is the sum of both the area of the tomato patch and the bell pepper patch. So:

</span>Aar(x)=x^{2}+\frac{x(x+2)}{2} \rightarrow Aar(x)=x^{2}+ \frac{x^{2}}{2}+x \rightarrow Aar(x)=\frac{3x^{2}}{2}+x \\ \\ \therefore \boxed{Aar(x)=\frac{x(3x+2)}{2}}
<span>
4. W</span>rite the function Aa(x) for the remaining planting area in the garden.

The remaining planting area in the garden are the rectangles in red. So we need to subtract the width of the bell pepper patch from the width of the tomato patch and multiply it by 2. In mathematical language this is given by:<span>

</span>Aa(x)=2(x-\frac{x}{2}) \rightarrow Aa(x)=x

5. 
Find the area of the remaining space in the garden after planting tomatoes and bell peppers.

Given that <span>Melissa wants the area of the bell pepper patch to be 31.5 square feet, then it is true that:

</span>31.5=\frac{x(x+2)}{2} \rightarrow x^{2}+2x-64=0 \\ \\ solving \ for \ x: \\ x=7.06
<span>
Therefore the area of the remaining space is:

</span>\boxed{Aa(7.06)=7.06ft^{2}}

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Your band is one of 8 bands competing at the battle of the bands. The order of the performances is determined at random. The fir
lorasvet [3.4K]

Answer:

1.79 %.

Step-by-step explanation:

you have to calculate the probability of a series of events before you can calculate the final probability.

The first event is that the band plays on Friday.

If there are 8 bands, but only 5 play on Friday, then the probability that they will play on Friday is

5/8

Now, the second event that they are the last ones is 1/5, since they are 5 bands.

Therefore the probability that they will play on Saturday and last is

5/8 * 1/5 = 1/8

Now, for the rival band it would be, knowing that on Friday there is already a quota assigned and one band less, the probability that they will play that day is

4/7

as they play before the other group, it would be 1/4, as there is already a quota assigned.

The final probability would then be:

4/7 * 1/4 = 1/7

Now the probability that the band gives the last performance on Friday night and your rival band performs immediately before them, is:

1/8 * 1/7 = 0.0179

That is 1.79 %.

3 0
2 years ago
Someone explain and help pls
jasenka [17]
Your answer for the girls in the gymnastics club is correct.

Do the percentage of water the same way:  Divide 139 by 197.
That'll give you the decimal amount that's covered by water.
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7 0
2 years ago
20c + 8d +10c - 5d<br><br><br> please answer you would get 15 points!
Rudik [331]
I think 30c+3d would be the correct answer.
4 0
1 year ago
Read 2 more answers
Find the size of each of two samples (assume that they are of equal size) needed to estimate the difference between the proporti
lesya [120]

Answer:

a) the sample size (n) = 156.25≅ 156

Step-by-step explanation:

<u>Step1 </u>:-

Given the two sample sizes are equal so n_{1} =n_{2} = n

Given the standard error (S.E) = 0.04

The standard error of the proportion of the given  sample size

S.E = \sqrt{\frac{pq}{n} }

Step 2:-

here we assume that the proportion of boys and girls are equally likely

p= 1/2 and q= 1/2

S.E = \sqrt{\frac{p(1-p)}{n} } \leq \frac{\frac{1}{2} }{\sqrt{n} }

\sqrt{n} = \frac{\frac{1}{2} }{S.E}

squaring on both sides, we get

n = \frac{1}{(2X0.04)^{2} }

on simplification, we get

n= 156.25 ≅ 156

sample size (n) = 156

<u>verification</u>:-

S.E = \sqrt{\frac{pq}{n} }= \sqrt{\frac{1}{4X156} } =\sqrt{0.0016}  

Standard error = 0.04

4 0
1 year ago
Leo is constructing a tangent line from point Q to circle P. What is his next step? circle P and point Q on the outside of circl
xxMikexx [17]

Answer:

The correct option is;

Construct a circle from point R with the radius RP

Step-by-step explanation:

To draw a tangent, the following steps are required

1) A line is drawn connecting the point to the center of the circle to which the tangent is to be drawn

2) The perpendicular bisector of the line constructed to get the mid point of the line

3) From the midpoint of the line found in the step above the compass is adjusted to reach the center of the given circle and a circular arc is drawn across the circumference of the given circle

4) The point of intersection of the arcs and the circumference of the given circle are the tangent points

Therefore, the correct option is to construct a circle from point R with the radius RP.

3 0
1 year ago
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