Answer:
The lateral area is equal to
Step-by-step explanation:
In this problem the lateral area is equal to the area of one equilateral triangle multiplied by 
To find the area of one equilateral triangle calculate the height
The area of the triangle is equal to
we have
Applying the Pythagoras theorem
The area of one triangle is equal to
so
The lateral area is equal to
Maybe by useing cubes like 6 groups of 17 or u can also use a number line like the elementary skills
Find, correct to the nearest degree, the three angles of the triangle with the vertices d(0,1,1), e( 2, 4,3) − , and f(1, 2, 1)
Ksju [112]
Well, here's one way to do it at least...
<span>For reference, let 'a' be the side opposite A (segment BC), 'b' be the side opposite B (segment AC) and 'c' be the side opposite C (segment AB). </span>
<span>Let P=(4,0) be the projection of B onto the x-axis. </span>
<span>Let Q=(-3,0) be the projection of C onto the x-axis. </span>
<span>Look at the angle QAC. It has tangent = 5/4 (do you see why?), so angle A is atan(5/4). </span>
<span>Likewise, angle PAB has tangent = 6/3 = 2, so angle PAB is atan(2). </span>
<span>Angle A, then, is 180 - atan(5/4) - atan(2) = 65.225. One down, two to go. </span>
<span>||b|| = sqrt(41) (use Pythagorian Theorum on triangle AQC) </span>
<span>||c|| = sqrt(45) (use Pythagorian Theorum on triangle APB) </span>
<span>Using the Law of Cosines... </span>
<span>||a||^2 = ||b||^2 + ||c||^2 - 2(||b||)(||c||)cos(A) </span>
<span>||a||^2 = 41 + 45 - 2(sqrt(41))(sqrt(45))(.4191) </span>
<span>||a||^2 = 86 - 36 </span>
<span>||a||^2 = 50 </span>
<span>||a|| = sqrt(50) </span>
<span>Now apply the Law of Sines to find the other two angles. </span>
<span>||b|| / sin(B) = ||a|| / sin(A) </span>
<span>sqrt(41) / sin(B) = sqrt(50) / .9080 </span>
<span>(.9080)sqrt(41) / sqrt(50) = sin(B) </span>
<span>.8222 = sin(B) </span>
<span>asin(.8222) = B </span>
<span>55.305 = B </span>
<span>Two down, one to go... </span>
<span>||c|| / sin(C) = ||a|| / sin(A) </span>
<span>sqrt(45) / sin(C) = sqrt(50) / .9080 </span>
<span>(.9080)sqrt(45) / sqrt(50) = sin(C) </span>
<span>.8614 = sin(C) </span>
<span>asin(.8614) = C </span>
<span>59.470 = C </span>
<span>So your three angles are: </span>
<span>A = 65.225 </span>
<span>B = 55.305 </span>
<span>C = 59.470 </span>
Answer:
An adult Welsh Corgi is always going to be shorter than an adult Basset Hound.
Step-by-step explanation:
That's what I think because the Basset Hound is 13.8 in. in height right? So he's two inches taller if we round up both numbers. Basset hound would be 14 and welsh corgi would be 11....................okay im not sure i give up but it's either
"An adult Welsh Corgi is always going to be shorter than an adult Basset Hound."
"Basset hounds tend to be a little over two inches taller than Welsh Corgis, but have a higher variability in height.
whichever just not the other ones good luck!
Answer:
Answer:
tha answer is d .
Step-by-step explanation:
i did this test
Step-by-step explanation:
