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mr Goodwill [35]
2 years ago
13

The following model can be used to study whether campaign expenditures affect election outcomes: voteA = β0 + β1log(expendA) + β

2log(expendB) + β3prtystrA + u where voteA is the percentage of the vote received by Candidate A, expendA and expendB are campaign expenditures by Candidates A and B, and prtystrA is a measure of party strength for Candidate A (the percentage of the most recent presidential vote that went to A0s party). (i) What is the interpretation of β1? (ii) In terms of the parameters, state the null hypothesis that a 1% increase in A0s expenditures is offset by a 1% increase in B0s expenditures

Mathematics
1 answer:
rosijanka [135]2 years ago
6 0

Answer:

(i) It represents change in expenditure by candidates A; (ii) H_0:\beta_1+\beta_2=0

Step-by-step explanation:

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The mean weight of newborn infants at a community hospital is 6.6 pounds. A sample of seven infants is randomly selected and the
Lera25 [3.4K]

Answer:

The correct option is  A

Step-by-step explanation:

From the question we are told that

    The  population is  \mu  =  6.6

     The level of significance is \alpha  =  5\%  = 0.05

      The sample data is  9.0, 7.3, 6.0, 8.8, 6.8, 8.4, and 6.6 pounds

The Null hypothesis is H_o  :  \mu =  6.6

 The Alternative hypothesis is  H_a :  \mu  > 6.6

The critical value of the level of significance obtained from the normal distribution table is

                       Z_{\alpha } = Z_{0.05 } = 1.645

Generally the sample mean is mathematically evaluated as

      \=x =  \frac{\sum x_i }{n}

substituting values

      \=x =  \frac{9.0 +  7.3 +  6.0+ 8.8+ 6.8+ 8.4+6.6 }{7}

      \=x =  7.5571

The standard deviation is mathematically evaluated as

           \sigma  =  \sqrt{\frac{\sum  [ x -  \= x ]}{n} }

substituting values

          \sigma  =  \sqrt{\frac{  [ 9.0-7.5571]^2 + [7.3 -7.5571]^2 + [6.0-7.5571]^2 + [8.8- 7.5571]^2 + [6.8- 7.5571]^2 + [8.4 - 7.5571]^2+ [6.6- 7.5571]^2 }{7} }\sigma =  1.1774

Generally the test statistic is mathematically evaluated as

            t  =  \frac{\= x - \mu }  { \frac{\sigma }{\sqrt{n} } }

substituting values

           t  =  \frac{7.5571  - 6.6  }  { \frac{1.1774 }{\sqrt{7} } }

            t  = 1.4274

Looking at the value of  t and  Z_{\alpha }   we see that t  <  Z_{\alpha } hence we fail to reject the null hypothesis

  What this implies is that there is no sufficient evidence to state that the sample data show as significant increase in the average birth rate

The conclusion is that the mean is  \mu = 6.6  \ lb

8 0
2 years ago
The student council at Spend too much High School is planning a school dance. The table below shows the budget for the dance.
hodyreva [135]
$300 income
$250 + $100 = $350 expenses

$300 - $350 = a loss of $50
6 0
2 years ago
Read 2 more answers
A marketing firm wants to estimate how much root beer the average teenager drinks per year. A previous study found a standard de
Verdich [7]

Answer:

At least 832 teenargers must be interviewed.

Step-by-step explanation:

We have that to find our \alpha level, that is the subtraction of 1 by the confidence interval divided by 2. So:

\alpha = \frac{1-0.99}{2} = 0.005

Now, we have to find z in the Ztable as such z has a pvalue of 1-\alpha.

So it is z with a pvalue of 1-0.005 = 0.995, so z = 2.575

Now, find the margin of error M as such

M = z*\frac{\sigma}{\sqrt{n}}

In which \sigma is the standard deviation of the population and n is the size of the sample.

How many teenagers must the firm interview in order to have a margin of error of at most 0.1 liter when constructing a 99% confidence interval

At least n teenargers must be interviewed.

n is found when M = 0.1.

We have that \sigma = 1.12

So

M = z*\frac{\sigma}{\sqrt{n}}

0.1 = 2.575*\frac{1.12}{\sqrt{n}}

0.1\sqrt{n} = 2.575*1.12

\sqrt{n} = \frac{2.575*1.12}{0.1}

(\sqrt{n})^{2} = (\frac{2.575*1.12}{0.1})^{2}

n = 831.7

Rounding up

At least 832 teenargers must be interviewed.

4 0
2 years ago
A grocery sold 5kg of wheat flour at Rs30 per kg and gained 20%. If he had sold it at Rs27 per kg, what would be his gain or los
maria [59]

Answer:

His gain percent would have been 8%

Step-by-step explanation:

The key to answering this question is to first calculate the price at which the wheat flour was bought.

Mathematically;

% profit = (selling price-cost price)/cost price * 100%

Let the cost price be $x

Thus;

% profit = (30-x)/x * 100

20 = 100(30-x)/x

20x = 3000-100x

100x + 20x = 3000

120x = 3000

x = 3000/120

x = Rs 25

So let’s assume he sold at Rs 27

His profit would have been 27-25 = 2

His gain or loss percentage would’ve been;

2/25 * 100/1 = 200/25 = 8% (gain, since selling price is greater than the cost price)

3 0
2 years ago
A spherical ball just fits inside a cylindrical can that is 10 centimeters tall, with a diameter of 10 centimeters. Which expres
egoroff_w [7]

Check the picture below.

\bf \textit{volume of a sphere}\\\\ V = \cfrac{4\pi r^3}{3}~~ \begin{cases} r=radius\\[-0.5em] \hrulefill\\ r = 5 \end{cases}\implies V=\cfrac{4\pi (5)^3}{3} \\\\\\ V=\cfrac{500\pi }{3}\implies V\approx 523.6

7 0
2 years ago
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