Answer: 0.8313
Step-by-step explanation:
As per given we have,
Also, the distribution of the number of suitcases that get lost each week on a certain route is approximately normal.
Since , 
z-score corresponds to x= 10:
z-score corresponds to x= 20:
P-value = 
Hence, the probability that during a given week the airline will lose between 10 and 20 suitcases = 0.8313
Answer:
16.30 ft ≈ 16 ft 4 in
Step-by-step explanation:
Please see the image attached. According to the figure, AB is the leaning flag. When the sun is directly overhead at noon, the shadow of the flag is the line AC in the figure. The length of AC is 5ft. The length of the string of plumb bob is 3ft and this is represented by the line XY. Y is the point of the plumb bob and this is at a distance of 11 in ( = 
ft from the base of the flag, i.e, AY = 0.92ft.
Now, the angle between the AB and AC is taken as ∅. In traingle AXY, tan(∅) = 
. In triangle ABC, for the same ∅, tan(∅) = 
. Therefore, tan(∅) = 
. Here, XY = 3ft, AY = 0.92ft, AC = 5ft.
Therefore, 
×5 = 16.30 ft ≈ 16 ft 4 in.
Answer:
(D) Two players of equal skill level each played one game a day for 50 days and their skill level did not change from day to day.
Step-by-step explanation:
(A) If the player's skill improves over time, the likelihood of him winning the game also increases and, therefore, this scenario cannot be modeled by a random binomial probability.
(B) Since the players have different skill levels, the likelihood of winning each game would change between players, thus X is not a binomial random variable.
(C) Same explanation as alternative B
(D) Since both players have the same constant skill level throughout all games, the likelihood of winning each of the 100 games is the same; therefore, X is a binomial random variable
(E) Same explanation as alternatives B and C
