Ask question

Ask question

All categories

2 years ago

11

at the track meet Jacob and Daniel compete in the 220m- hurdles Daniel finishes in 3 fourths of a minute. Jacob finishes with 5

twelves minute remaining.who ran the race in the faster time.

1 answer:

jeka942 years ago

8 0

Daniel because 3/4 is larger than 5/12 if you cross multiply.

You might be interested in

Divide 32x4 − 12x2 + 7x by 2x.

Katen [24]

(32x⁴ - 12x² + 7x) / 2x

32x⁴/2x - 12x²/2x + 7x/2x

16x³ - 6x + 7/2

4 0

2 years ago

15 kilograms of rice are separated equally into 4 containers. How many kilograms of rice are in each container? Express your ans

Nadusha1986 [10]

Answer: Fraction= 3 3/4kg

Decimal= 3.75kg

Step-by-step explanation:

15 kilograms of rice are separated equally into 4 containers. To get the number of kilograms of rice are in each container, we divide the total kilograms of rice by the number of containers. This will be:

Kilograms of rice in each container=

15/4 =3 3/4kg as a fraction.

To convert the fraction to decimal, we divide 3 by 4 and add to 3. 3/4 equals 0.75. We then add 3 to 0.75. This will be:

Decimal of 3 3/4 = 3+0.75 = 3.75kg

7 0

2 years ago

A group of students formed a circle during a game.The circumference of the circle was about 43.96 feet,and the diameter of the c

Alchen [17]

Answer:

A group of students formed a circle during a game.The circumference of the circle was about 43.96 feet,and the diameter of the circle was 14 feet.Which expression best represents the value of π?

The expression which represents the value of π is option C from the attachment that is π = 43.96/14

Step-by-step explanation:

Given:

Circumference of the circle = 43.96 feet

Diameter f the circle = 14 feet

So,

We know that :

Circumference of the circle = $2(\pi )r$ or $(\pi)d$

Re-arranging the formula:

⇒ $(\pi)d = Circumference\ (C)$

⇒ $(\pi )d =C$

⇒ $\frac{\pi\times d}{d}=\frac{C}{d}$

⇒ $\pi =\frac{C}{d}$

Plugging the numeric values:

⇒ $\pi =\frac{43.96}{14}$

So the expression for π is 43.96/ 14,and option C is the correct choice.

4 0

1 year ago

four times the first of three consecutive odd integers is five less than the product of three and the third integer find the int

Andre45 [30]

I don't understand what integer is being asked for. The question is poorly worded.

The three integers are 7, 9, 11.
4 times 7 = 28
and 3 times 11 = 33
and 28 is 5 less than 33.

8 0

1 year ago

Two professors are applying for grants. Professor Jane has a probability of 0.61 of being funded. Professor Joe has probability

Anna11 [10]

Answer:

a. 0.1647;
b. 0.7153;
c. 0.4453.

Step-by-step explanation:

By definition, if two event $A$ and $B$ are independent, then

$P(A\cap B) = P(A) \cdot P(B)$ . ( $P(A\cap B)$ is the probability that the outcome of both event $A$ and event $B$ are true.)

<h3>a.</h3>

Since the outcome of these two events are independent,

$\begin{aligned}P(\texttt{Jane} \cap \texttt{Joe}) &= P(\texttt{Jane}) \cdot P(\texttt{Joe})\\ &= 0.61 \times 0.27 \\&= 0.1647\end{aligned}$ .

<h3>b.</h3>

The logic not operator $\lnot$ or the prime superscript $^{\prime}$ denotes that an event does not happen.

$P(\texttt{Jane}^{\prime}) = 1 - P(\texttt{Jane}) = 1- 0.61 = 0.39$ .

$P(\texttt{Joe}^{\prime}) = 1 - P(\texttt{Joe}) = 1- 0.27 = 0.73$ .

Since the two events $\texttt{Jane}$ and $\texttt{Joe}$ , $\texttt{Jane}^{\prime}$ and $\texttt{Joe}^{\prime}$ are also independent. Probability that neither professor got funded:

$P(\texttt{Jane}^{\prime} \cap \texttt{Joe}^{\prime}) = P(\texttt{Jane}^{\prime}) \cdot P(\texttt{Joe}^{\prime}) = 0.39 \times 0.73 = 0.2847$ .

Probability that at least one professor got funded- in other words, it is not true that neither professor got funded:

$P((\texttt{Jane}^{\prime} \cap \texttt{Joe}^{\prime})^{\prime}) = 1- P(\texttt{Jane}^{\prime} \cap \texttt{Joe}^{\prime}) = 0.7153$ .

<h3>c.</h3>

Similarly, since the two events $\texttt{Jane}$ and $\texttt{Joe}$ , $\texttt{Jane}$ and $\texttt{Joe}^{\prime}$ are also independent. Probability that Jane but not Joe got funded:

$P(\texttt{Jane} \cap (\texttt{Joe}^{\prime})) = P(\texttt{Jane}) \cdot P(\texttt{Joe}^{\prime}) = 0.61 \times 0.73 = 0.4453$ .

4 0

1 year ago