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Masteriza [31]
2 years ago
13

The graphs shown are of the form y = ax2. Which graph has the smallest value for a?

Mathematics
1 answer:
Talja [164]2 years ago
3 0
y= x^{2} is a parabola (looks like the letter U).

The letter a represents the coefficient of x^{2} and it controls two things (1) how wide or narrow the parabola is and (2) whether it is concave up (like a U) or concave down (like an up-side-down).

The absolute value of a (the number without the sign) controls how wide or narrow it is. If the absolute value is a fraction less than 1 the graph gets wider. The smaller the absolute value of the fraction the wider the graph gets.

If the absolute value of a is greater than 1 the graph gets narrower (it gets skinnier). The bigger the absolute value the narrower the graph.

So, if all the graphs look like a U (concave up) then the one with the smallest a is the one that is the widest.

The a also controls whether the graph is concave up or concave down. If a is negative

If a is negative the graph is concave down so any graph that is concave down has a smaller value of a than any graph that is concave up. However, if the graph is concave down the one with the smallest a would be the most narrow one.

So to find the one with the smallest a...
If they are all concave up (like a U) pick the widest one
and
If they are not all concave up pick the narrowest one that is concave down (looks like an upside down U)
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Given circle X with radius 10 units and chord AB with length 12 units, what is the length of segment CX, which bisects the chord
andrew-mc [135]
Consider the circle with center X, as shown in the figure. 

Draw the diameter of the circle which is parallel to cherd AB, as shown in the figure.

Since the diameter and AB are parallel, then the line segment XC which bisects AB at C, will be perpendicular to AB.

SO triangle XCB is a right triangle. Thus the length of CX, by the Pythagorean theorem is  

\sqrt{ XB^{2}- CB^{2}} = \sqrt{ 10^{2}- CB^{6}}= \sqrt{100-36}= \sqrt{64}=8 units.


Answer: 8 units

7 0
2 years ago
In 2004, a magazine's circulation was about 1,000,000 readers. In 2014, the magazine had about 2,000,000 readers. Write a linear
professor190 [17]

Answer:

r(t)=100,000t+600,000

Step-by-step explanation:

Let

r ----> the number of readers (y-coordinate or dependent variable)

t ----> the number of years after 2000 (x-coordinate or independent variable)

Remember

2004 ----> represent t=4 years

2014 ----> represent t=14 years

we have the ordered pairs

(4,1,000,000) and (14,2,000,000)

step 1

Find the slope

The formula to calculate the slope between two points is equal to

m=\frac{y2-y1}{x2-x1}

substitute the values

m=\frac{2,000,000-1,000,000}{14-4}

m=\frac{1,000,000}{10}

m=100,000\frac{readers}{year}

step 2

Find the equation of the line in point slope form

r-r1=m(t-t1)

we have

m=100,000\\point\ (4,1,000,000)

substitute

r-1,000,000=100,000(t-4)

step 3

Convert to slope intercept form

r=mt+b

isolate the variable r

r-1,000,000=100,000t-400,000\\r=100,000t-400,000+1,000,000\\r=100,000t+600,000

step 4

Convert to function notation

r(t)=100,000t+600,000

6 0
1 year ago
Suppose f and g are continuous functions such that g(2) = 6 and lim x → 2 [3f(x) + f(x)g(x)] = 36. find f(2).
True [87]

Answer: f(2) = 4

Step-by-step explanation:

F(x) and g(x) are said to be continuous functions

Lim x=2 [3f(x) + f(x)g(x)] = 36

g(x) = 2

Limit x=2

[3f(2) + f(2)g(2)] = 36

[3f(2) + f(2) . 6] = 36

[3f(2) + 6f(2)] = 36

9f(2) = 36

Divide both sides by 9

f(2) = 36/9

f(2) = 4

7 0
1 year ago
The area of the figure
STALIN [3.7K]
Rectangle:

4*8=32

Semicircle:

3.14*4^2= 50.24
50.24/2=25.12

Add:

25.12+32= 57.12

Final answer: A
5 0
2 years ago
Read 2 more answers
−3 1/3 ÷ 9 pllllllllllllllllllllllllllllllllllllllllllllllllll
tia_tia [17]

-\frac{10}{27}  hope this helps :)

8 0
2 years ago
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