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jeka94
2 years ago
12

−3 1/3 ÷ 9 pllllllllllllllllllllllllllllllllllllllllllllllllll

Mathematics
1 answer:
tia_tia [17]2 years ago
8 0

-\frac{10}{27}  hope this helps :)

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Morena is painting her bedroom and has a triangle of space left over as shown below. What is the area of the space Morena still
aleksandrvk [35]

The answer is Letter c

7 0
2 years ago
In a survey of students, 80% were girls and 20% were boys. of the girls surveyed, 40% were wearing sneakers. if a surveyed stude
prisoha [69]

Answer:

\frac{8}{25}

Step-by-step explanation:

probability of selecting a girl from students is \frac{4}{5}

probability of girl wearing sneaker from girls is \frac{4}{10} or \frac{2}{5}

hence, probability of selecting a girl wearing a sneaker will be,

⇒ probability = probability of delecting a girl from students × probability of girl wearing sneakers from girls

⇒ probability = (\frac{4}{5})( \frac{2}{5})

⇒ probability = \frac{8}{25}

3 0
2 years ago
The power generated by an electrical circuit (in watts) as a function of its current x xx (in amperes) is modeled by P ( x ) = −
marysya [2.9K]

Given:

The power generated by an electrical circuit (in watts) as a function of its current x (in amperes) is modeled by

P(x)=-15x(x-8)

To find:

The current which will produce the maximum power.

Solution:

We have,

P(x)=-15x(x-8)

P(x)=-15x^2+120x

Differentiate with respect to x.

P'(x)=-15(2x)+120(1)

P'(x)=-30x+120      ...(i)

To find the extreme point equate P'(x)=0.

-30x+120=0

-30x=-120

Divide both sides by -30.

x=4

Differentiate (i) with respect to x.

P'(x)=-30(1)+(0)

P'(x)=-30 (Maximum)

It means, the given function is maximum at x=4.

Therefore, the current of 4 amperes will produce the maximum power.

7 0
2 years ago
Of 560 samples of seafood purchased from various kinds of food stores in different regions of a country and genetically compared
frutty [35]

Answer:

a) (0.5256,0.5944)  

c) Criticism is invalid

Step-by-step explanation:

We are given the following in the question:

Sample size, n = 560

Proportion of mislabeled = 56%

\hat{p} = 0.56

a) 90% Confidence interval:

\hat{p}\pm z_{stat}\sqrt{\dfrac{\hat{p}(1-\hat{p})}{n}}

z_{critical}\text{ at}~\alpha_{0.05} = \pm 1.64

Putting the values, we get:

0.56\pm 1.64(\sqrt{\dfrac{0.56(1-0.56)}{560}}) = 0.56\pm 0.0344\\\\=(0.5256,0.5944)

b) Interpretation of confidence interval:

We are 90% confident that the true proportion of all seafood in the country that is mislabeled or misidentified is between 0.5256 and 0.5944 that is 52.56% and 59.44%.

c) Validity of criticism

Conditions for validity:

np > 10\\n(1-p)>10

Verification:

560\times 0.56 = 313.6>10\\560(1-0.56) = 246.4>10

Both the conditions are satisfied. This, the criticism is invalid.

8 0
2 years ago
Sal's Sandwich Shop sells wraps and sandwiches as part of its lunch specials. The profit on every sandwich is $2 and the profit
KIM [24]
<span>Since both functions follow the form of 2X + 3Y = c in general, where c is some constant, both functions will have the same slope as of -2/3. However, both graph will not have the same Y-intercept as the profits are different. Similarly, the X-intercept will also be different due to the profits.

I hope my answer has come to your help. Have a nice day ahead and may God bless you always!
</span>
8 0
2 years ago
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