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Bad White [126]
2 years ago
6

Emma wants to estimate the percentage of people who use public transportation in a city. She surveys 140 individuals and finds t

hat 62 use public transportation. Use a calculator to find the confidence interval for the population proportion with a 99% confidence level. Round the final answer to three decimal places.
Mathematics
1 answer:
jolli1 [7]2 years ago
7 0

nmmn,.Answer:

mn,./.,m.mn,.mn,lm

Step-by-step explanation:

lk;lkjhgbnm,jnhgfhjnmjkhgfdedrftgyhjkljhugyft

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A rectangular state flag has dimensions 7 feet by 5 1/2 feet. How long is its diagonal? Round your answer to the nearest tenth i
slamgirl [31]
The formula for a diagonal of a rectangle is <span>√w^2+h^2, with w and h being the width and height. Plug in your numbers to get </span><span>√7^2+5.5^2. Simplify that into </span><span>√49+30.25, then to </span><span>√79.25. Use your calculator to get 8.9022. The diagonal is 8.9 feet.</span>
5 0
2 years ago
Thomas purchased a bag of marbles on Monday. On Tuesday he gave half of the marbles to his brother. On Wednesday he gave eight m
kupik [55]

Answer:

168

Step-by-step explanation:

60+16+8 is 84

84 times 2 is 168

Mark me as brainliest if this helps!

6 0
2 years ago
What is the value of the expression i 0 × i 1 × i 2 × i 3 × i 4?
astraxan [27]
ANSWER


The value of the expression is
- 1


EXPLANATION

Method 1: Rewrite as product of
{i}^{2}


The expression given to us is,

{i}^{0}  \times {i}^{1}  \times {i}^{2}  \times {i}^{3}  \times {i}^{4}


We use the fact that
{i}^{2}  =  - 1
to simplify the above expression.



{i}^{0}  \times {i}^{1}  \times {i}^{2}  \times {i}^{3}  \times {i}^{4}  =  {i}^{0}  \times {i}^{1}  \times {i}^{3}   \times {i}^{2}   \times {i}^{4}


This implies,


{i}^{0}  \times {i}^{1}  \times {i}^{2}  \times {i}^{3}  \times {i}^{4}  =  {i}^{0}  \times {i}^{2}  \times {i}^{2}   \times {i}^{2}   \times {i}^{2} \times {i}^{2}


We substitute to obtain,

{i}^{0}  \times {i}^{1}  \times {i}^{2}  \times {i}^{3}  \times {i}^{4}  =  1\times  - 1 \times  - 1  \times  - 1\times  - 1 \times  - 1


{i}^{0}  \times {i}^{1}  \times {i}^{2}  \times {i}^{3}  \times {i}^{4}  =  1\times  1 \times   1  \times  - 1 =  - 1


Method 2: Use indices to solve.



{i}^{0}  \times {i}^{1}  \times {i}^{2}  \times {i}^{3}  \times {i}^{4}  = {i}^{0 + 1 + 2 + 3 + 4}



This implies that,


{i}^{0}  \times {i}^{1}  \times {i}^{2}  \times {i}^{3}  \times {i}^{4}  = {i}^{10}




{i}^{0}  \times {i}^{1}  \times {i}^{2}  \times {i}^{3}  \times {i}^{4}  =  (  {{i}^{2}} )^{5}


{i}^{0}  \times {i}^{1}  \times {i}^{2}  \times {i}^{3}  \times {i}^{4}  =  (   - 1 )^{5}   =  - 1


8 0
2 years ago
Read 2 more answers
A toy rocket is launched from a platform 33 feet above the ground at a speed of 83 feet per second. The height of the rocket in
kiruha [24]

Answer:

282ft

Step-by-step explanation:

83×3=249

249+33=282

4 0
2 years ago
The number of defective components produced by a certain process in one day has a Poisson distribution with a mean of 20. Each d
Kruka [31]

Answer:

The probability that exactly 15 defective components are produced in a particular day is 0.0516

Step-by-step explanation:

Probability function : P(X=x)=e^{-\lambda} \frac{\lambda^x}{x!}

We are given that The number of defective components produced by a certain process in one day has a Poisson distribution with a mean of 20.

So,\lambda = 20

we are supposed to find the probability that exactly 15 defective components are produced in a particular day

So,x = 15

Substitute the values in the formula :

P(X=15)=e^{-20} \frac{20^{15}}{15!}

P(X=15)=e^{-20} \frac{20^{15}}{15!}

P(X=15)=0.0516

Hence the probability that exactly 15 defective components are produced in a particular day is 0.0516

8 0
2 years ago
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