Answer:
16 in.
Step-by-step explanation:
We have the ratio
How about let's make this easier. Easier is better, right? Let's get rid of the fraction 2/3. We will do that by multiplying 2/3 by 3 and 1 by 3 to get the equivalent ratio of
Now we need to know how many inches there would be if the number of feet is 24:
Cross multiply to get
3x = 48 so
x = 16 in.
Answer:
3 - (n - 1) = 1/2(3n - 4)
Step-by-step explanation:
We want to write three minus the difference of a number and one equals one-half of the difference of three times the same number and four as an equation.
Let the number be n.
The first part is: three minus the difference of a number and one:
3 - (n - 1)
The second part is: one-half of the difference of three times the same number and four:
1/2(3n - 4)
Now, let us equate the first and second parts:
3 - (n - 1) = 1/2(3n - 4)
PS: I really do not understand the options
Weight = k/(distance)². Let's find the value of k when distance = earth radius:
180 = k/(3900)² → k = 180 x 3900² → k = 2,737,800,000
If he is at 325 miles ABOVE the earth, the distance becomes: 3,900+325=4,225 miles and his weight becomes:
Weight = k/(distance)² → Weight = 2,737,800,000/(4225)² = 153.37
Weight = 153.37 lb
Answer:
1) The probability that ten students in a class have different birthdays is 0.883.
2) The probability that among ten students in a class, at least two of them share a birthday is 0.002.
Step-by-step explanation:
Given : Assume there are 365 days in a year.
To find : 1) What is the probability that ten students in a class have different birthdays?
2) What is the probability that among ten students in a class, at least two of them share a birthday?
Solution :
Total outcome = 365
1) Probability that ten students in a class have different birthdays is
The first student can have the birthday on any of the 365 days, the second one only 364/365 and so on...
The probability that ten students in a class have different birthdays is 0.883.
2) The probability that among ten students in a class, at least two of them share a birthday
P(2 born on same day) = 1- P( 2 not born on same day)
![\text{P(2 born on same day) }=1-[\frac{365}{365}\times \frac{364}{365}]](https://tex.z-dn.net/?f=%5Ctext%7BP%282%20born%20on%20same%20day%29%20%7D%3D1-%5B%5Cfrac%7B365%7D%7B365%7D%5Ctimes%20%5Cfrac%7B364%7D%7B365%7D%5D)
![\text{P(2 born on same day) }=1-[\frac{364}{365}]](https://tex.z-dn.net/?f=%5Ctext%7BP%282%20born%20on%20same%20day%29%20%7D%3D1-%5B%5Cfrac%7B364%7D%7B365%7D%5D)
The probability that among ten students in a class, at least two of them share a birthday is 0.002.
So we know that the width is 12 because 4 x 3 = 12. The formula to find the perimeter is Length + length + width + width. So you would do 3 + 3 + 12 + 12 = 30. Therefore the perimeter is 30 inches
