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telo118 [61]
1 year ago
9

17. It takes one minute to fill (3/7) th of a vessel. What is the time taken in

Mathematics
1 answer:
Vinil7 [7]1 year ago
8 0

Answer:

Given that 1minute =3/7of the vessel

let the time taken in minutes to fill the whole of the vessel be' x' minute.

1min =3/7

xmin =whole vessel =1=7/7

=3x/7=1=x=7/3=2.3min=2min.3sec

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What is the length of Line segment A B? Round to the nearest tenth. Triangle A B C is shown. Angle A C B is a right angle and an
amm1812

C=90°, A=75°, b=AC=19, x=AB

Without a figure, we see AC is adjacent to angle A, so

cos A = AC/AB = b/x

x = b/cos A = 10 / cos 75° ≈ 38.637

Answer: 38.6

3 0
1 year ago
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After years of maintaining a steady population of 32,000, the population of a town begins to grow exponentially. After 1 year an
galben [10]

Answer:

y=32000(1+0.08)^x

Step-by-step explanation:

Exponential growth function is y=a(1+r)^x

Where 'a' is the initial population

r is the rate of growth and x is the time period in years

a steady population of 32,000. So initial population is 32,000

an increase of 8% per year. the rate of increase is 8% that is 0.08

a= 32000 and r= 0.08

Plug in all the values in the general equation

y=a(1+r)^x

y=32000(1+0.08)^x

y=32000(1+0.08)^x

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1 year ago
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For several hours you watch a group playing dice on the street and you notice that the owner of the dice often wins. do you conc
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The owner is most likely cheating because it is usually a 50|50 chance of winning. But, you usually only get 50, and win a bit less and loose more. So, he is most likely cheating. (Hope this helped  :D)
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2 years ago
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Sammy has a 10-foot ladder, which he needs to climb to reach the roof of his house. the roof is 12 feet above the ground. the ba
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2 years ago
A company wants to establish that the mean life of its batteries, when used in a wireless mouse, is over 183 days. The data will
enyata [817]

Answer:

a) Null and alternative hypotheses are:

H_{0}: mu=183 days

H_{a}: mu>183 days

b) If the true mean is 190 days, Type II error can be made.

Step-by-step explanation:

Let mu be the mean life of the batteries of the company when it is used in a wireless mouse

Null and alternative hypotheses are:

H_{0}: mu=183 days

H_{a}: mu>183 days

Type II error happens if we fail to reject the null hypothesis, when actually the alternative hypothesis is true.

That is if we conclude that mean life of the batteries of the company when it is used in a wireless mouse is at most 183 days, but actually mean life is 190 hours, we make a Type II error.

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2 years ago
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