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motikmotik
2 years ago
5

At a convention of monsters, 2/5 have no horns, 1/7 have one horn, 1/3 have two horns, and the remaining 26 have three or more h

orns. How many monsters are attending the convention?
Mathematics
1 answer:
Kazeer [188]2 years ago
4 0
If we take it that, the total amount is say hmmm "x"
then one can say that \bf \begin{cases}
\cfrac{2}{5}x\impliedby &\textit{no horns}\\\\
\cfrac{1}{7}x\impliedby &\textit{one horn}\\\\
\cfrac{1}{3}x\impliedby &\textit{two horns}\\\\
26\impliedby &remaining
\end{cases}
\\\\\\
\textit{so the total is really }\quad \cfrac{2}{5}x+\cfrac{1}{7}x+\cfrac{1}{3}x+26

add up the fractions of "x" and the constant of 26

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2 years ago
M a right angle. 2 lines form a right angle. Another line extends between the 2 lines to form 2 angles. The top angle is labeled
siniylev [52]

Answer:

i think it's congruent .

Step-by-step explanation:

8 0
2 years ago
Which expression is equivalent to StartFraction (3 m Superscript negative 2 Baseline n) Superscript negative 3 Baseline Over 6 m
Dovator [93]

Option a: \frac{m^{5} }{162n} is the equivalent expression.

Explanation:

The expression is \frac{(3m^{-2} n)^{-3}}{6mn^{-2} } where m\neq 0, n\neq 0

Let us simplify the expression, to determine which expression is equivalent from the four options.

Multiplying the powers, we get,

\frac{3^{-3}m^{6} n^{-3}}{6mn^{-2} }

Cancelling the like terms, we have,

\frac{3^{-3}m^{5} n^{-1}}{6 }

This equation can also be written as,

\frac{m^{5}}{3^{3}6 n^{1} }

Multiplying the terms in denominator, we have,

\frac{m^{5} }{162n}

Thus, the expression which is equivalent to \frac{(3m^{-2} n)^{-3}}{6mn^{-2} } is \frac{m^{5} }{162n}

Hence, Option a is the correct answer.

8 0
2 years ago
Read 2 more answers
The exhaust system of an automobile is first given an emission check and then given a vibration check. The result of an emission
Andre45 [30]

Answer:

Step-by-step explanation:

The sample space is known to be the set of all possible outcomes of an experiment we cannot predict its outcome while the event space showcases the subset of the sample space, this may be a collection of outcomes of a random experiment.

From the given information:

The sample space = {SH, SL, SN, MH, ML, MN,UH, UL, UN}

The event that the emissions check is satisfactory = {SH, SL, SN}

8 0
1 year ago
Which shows the correct substitution of the values a, b, and c from the equation 0 = – 3x2 – 2x + 6 into the quadratic formula?
lbvjy [14]

Answer:

x = StartFraction negative

(negative 2) plus or minus StartRoot (negative 2) squared minus 4 (negative 3)(6) EndRoot Over 2(negative 3) EndFraction

Step-by-step explanation:

0 = – 3x2 – 2x + 6

It can still be written as

– 3x2 – 2x + 6 =0

Quadratic formula=

-b+or-√b^2-4ac/2a

Where

a=-3

b=-2

c=6

x= -(-2)+ or-√(-2)^2-4(-3)(6)/2(-3)

x = StartFraction negative

(negative 2) plus or minus StartRoot (negative 2) squared minus 4 (negative 3)(6) EndRoot Over 2(negative 3) EndFraction

8 0
2 years ago
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