I believe this would take the form of an exponential
equation:
A = Ao (1 + r)^t
where A is final population, Ao is initial population, r
is rate of growth and t is time
A / Ao = (1 + r)^t
log A / Ao = t log (1 + r)
t = (log A / Ao) / log (1 + r)
t = [log (1000 / 550)] / log (1.075)
t = 8.27 years
SO the answer is B) about 9 years
<span>The number of dollars collected can be modelled by both a linear model and an exponential model.
To calculate the number of dollars to be calculated on the 6th day based on a linear model, we recall that the formula for the equation of a line is given by (y - y1) / (x - x1) = (y2 - y1) / (x2 - x1), where (x1, y1) = (1, 2) and (x2, y2) = (3, 8)
The equation of the line representing the model = (y - 2) / (x - 1) = (8 - 2) / (3 - 1) = 6 / 2 = 3
y - 2 = 3(x - 1) = 3x - 3
y = 3x - 3 + 2 = 3x - 1
Therefore, the amount of dollars to be collected on the 6th day based on the linear model is given by y = 3(6) - 1 = 18 - 1 = $17
To calculate the number of dollars to be calculated on the 6th day based on an exponential model, we recall that the formula for exponential growth is given by y = ar^(x-1), where y is the number of dollars collected and x represent each collection day and a is the amount collected on the first day = $2.
8 = 2r^(3 - 1) = 2r^2
r^2 = 8/2 = 4
r = sqrt(4) = 2
Therefore, the amount of dollars to be collected on the 6th day based on the exponential model is given by y = 2(2)^(5 - 1) = 2(2)^4 = 2(16) = $32</span>
We look at what is provided and our answers give us a clue on this. We see we are to compare using fractions...always being the part / whole. This is so we can compare to make similarities...
B....RY/RS = RX/RT = XY/TS
The original price was 65
