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andrey2020 [161]
2 years ago
13

Write an expression for the calculation subtract 12 doubled from 132

Mathematics
2 answers:
bazaltina [42]2 years ago
7 0
 the answer is 
0.091 in the problem

Anon25 [30]2 years ago
6 0

Doubled of 132 which means 2 times 132 = 132\times 2

Subtract 12 doubled from 132

While write the expression whatever the expression after the word from that we have to write first

So Doubled of 132 - 12

( 132\times 2  ) - 12 -----> This is the final expression

If we simplify the above expression we will get

264 - 12

= 252


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Answer:

1800

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Labor quantity variance= Actual quantity ×standard price - standard quantity ×standard price

Standard quantity=2×2600=5200

Labor quantity variance

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If JK LM , which statement is true ?
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7 0
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Read 2 more answers
If θ=0rad at t=0s, what is the blade's angular position at t=20s
babunello [35]
The attached figure represents the relation between ω (rpm) and t (seconds)
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              ω = 100 (rpm) = 100 * (2π/60) = (10/3)π    rad/s

and from the figure it is clear that the operation is at constant speed but with variable levels
            ⇒   ω = dθ/dt   ⇒   dθ = ω dt

            ∴    θ = ∫₀²⁰  ω dt  
 
while ω is not fixed from (t = 0) to (t =20)
the integral will divided to 3 integrals as follow;
       ω = 0                                          from t = 0  to t = 5
       ω = 250 (rpm) = (25/3)π            from t = 5   to t = 15
       ω = 100 (rpm) = (10/3)π            from t = 15 to t = 20

∴ θ = ∫₀⁵  (0) dt   + ∫₅¹⁵  (25/3)π dt + ∫₁₅²⁰  (10/3)π dt
     
the first integral = 0
the second integral = (25/3)π t = (25/3)π (15-5) = (250/3)π
the third integral = (10/3)π t = (25/3)π (20-15) = (50/3)π

∴ θ = 0 + (250/3)π + (50/3)π = 100 π

while the complete revolution = 2π
so instantaneously at t = 20
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Which mean:
the blade will be at zero position making no of revolution = (100π)/(2π) = 50
















3 0
2 years ago
With food prices becoming a great issue in the world; wheat yields are even more important. Some of the highest yielding dry lan
Rzqust [24]

Answer:

Option E) 61.6

Step-by-step explanation:

We are given the following information in the question:

Mean, μ = 100 bushels per acre

Standard Deviation, σ = 30 bushels per acre

We assume that the distribution of yield is a bell shaped distribution that is a normal distribution.

Formula:

z_{score} = \displaystyle\frac{x-\mu}{\sigma}

P(X>x) = 0.90

We have to find the value of x such that the probability is 0.90

P(X > x)  

P( X > x) = P( z > \displaystyle\frac{x - 100}{30})=0.90  

= 1 -P( z \leq \displaystyle\frac{x - 100}{30})=0.90  

=P( z \leq \displaystyle\frac{x - 100}{30})=0.10  

Calculation the value from standard normal table, we have,  

P(z

\displaystyle\frac{x - 100}{30} = -1.282\\x = 61.55 \approx 61.6  

Hence, the yield of 61.6 bushels per acre or more would save the seed.

7 0
2 years ago
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