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Marat540 [252]
1 year ago
12

. Ralph’s Fill Dirt and Croissant Shop in Spencer makes both grand and petit croissants. Each grand requires 1 ounce of flour an

d 2 ounces of butter, while each petit requires only 1 4 ounce of flour and 1 3 ounce of butter. It is the end of the month and Ralph has only 4 ounces of flour and 6 ounces of butter. Ralph calculates how many of each type of croissant he should make in order to use all his ingredients. Determine the number of grand croissants Ralph calculated?
Mathematics
1 answer:
Gwar [14]1 year ago
7 0

Answer:

1

Step-by-step explanation:

let G be the number of grand croisssants, and P the number of petit croissants :

we have that 1 ounce of flour and 2 ounces of butter result in one G.

additionally, we have that 1/4 ounce of flour and 1/3 ounce of butter result in one P.

Ralph has 4 ounces of flour and 6 ounces of butter, If he bakes more than 1 G then he will never use all of his ingredients!, let's see:

1 G:

he now has 3 ounces of flour, and 4 ounces of butter,

now we need to figure out how many P's we would obtain with such amounts:

let x be the number of P's

1/4*x = 3=>x=12\\ 1/3*x=4=>x=12

which is reasonable, Ralph can bake 12 P's,

now with more than 1 G:

2G:

Ralph has now 2 ounces of flour and 2 ounces of butter, now we have to figure out that x is the same using the remaining ingredients

1/4*x = 2=>x=8\\ 1/3*x=2=>x=6

This is impossible.

3G:

he runs out of butter.

There is the answer, he is able to bake 1 grand croissant and 12 petit croissants

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The number 2^1993 + 3^1993 is a multiple of 5. What is the units digit of the quotient (2^1993 + 3^1993)/5?
Ad libitum [116K]

Answer: The unit digit of the quotient is 1.

Step-by-step explanation:

Since the number 2^1993 + 3^1993 is a multiple of 5, this means that no matter the value of the answer to the equation, the last digit will be 5 (we call the last digit of any number its "unit digit").

Since the unit digit of 2^1993 + 3^1993 is 5, if the unit digit is divided by 5 i.e 5/5, it will give us 1.

We will only consider the last digits of the multiple of 5 as our numerator

3 0
1 year ago
You just discovered that you have 100 feet of fencing and you have decided to make a rectangular garden. Assume the lengths of t
Tju [1.3M]

Answer:

10*10=100

50*2=100

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Step-by-step explanation:


3 0
1 year ago
A person is watching a boat from the top of a lighthouse. The boat is approaching the lighthouse directly. When first noticed, t
maksim [4K]

Answer:

Boat traveled 553.24 feet towards the lighthouse.

Step-by-step explanation:

In the figure attached AB is the light house of height 200 feet.

Angle of depression of the boat from the top of a lighthouse = angle of elevation of the lighthouse from the boat = 14°52'

so 1' = \frac{1}{60} degree

so angle of elevation at point C = 14 + \frac{52}{60}

So angle of elevation from C = (14 + 0.87) = 14.87°

Similarly, when boat arrives at point D angle of elevation = 45°10' = 45 + \frac{10}{60} = 45.17°

Now we have to calculate the distance CD, traveled by the boat.

In ΔABC

tan14.87 = \frac{200}{BC}

0.2655 =  \frac{200}{BC}

BC = \frac{200}{0.26552}

BC = 753.239 feet

Similarly in ΔABD

tan45.17 = \frac{200}{BD}

1 = \frac{200}{BD}

BD = 200 feet

So distance CD = BC - BD

CD = 753.239 - 200

     = 553.24 feet

Therefore, Boat traveled 553.24 feet towards the lighthouse.

7 0
1 year ago
Read 2 more answers
To increase sales, a local donut shop began putting an extra donut in some of the boxes. Customers are unaware of which boxes ha
Bingel [31]

Answer:

Step-by-step explanation:

Hello!

Part A

First, determine your study variable:

X: Number of boxes with an extra donut in a sample of eight.

To see if the variable has a Binomial distribution you have to check if the binomial criteria are met:

1. The number of observation of the trial is fixed (In this case n = 8, the boxes each customer bought make the sample)

2. Each observation in the trial is independent, this means that none of the trials will affect the probability of the next trial (In this case, the amount of donuts in one box does not affect on the probability of the next box having an extra donut)

3. The probability of success in the same from one trial to another (In this case our "success" will be that the box has an extra donut, according to the owners claim that is 1/7; ρ=0,14)

So X≈ Bi (n;ρ)

Where n represents the sample (n=8) and ρ is the probability of success (ρ=0.14)

Part B

The mean of the binomial distribution is E(X)= nρ

E(X)= 8 * 0.14= 1.12

The mean of the distribution is also called the expected value. You'd expect that 1.12 boxes have an extra donut.

The variance of the binomial distribution is V(X)= nρ(1 - ρ)

V(X)= 8*0.14*(1 - 0.14)= 0.9632

Its square root is the standard deviation

√V(X)= 0.98

The standard deviation is a measure of dispersion, it indicates how much the values ​​of the distribution of the central value are separated. In this case, 0.98 indicates that the distribution of the number of boxes with an extra donut is far from the expected value.

Part C

Two of the eight customers buy a box with an extra donut, symbolically:

P(X=2) = P(X≤2) - P(X≤1)= 0.91 - 0.68 = 0.22

There is a 22% chance that two customers bought a box with an extra donut.

Compute:

P(X≥2)= 1 - P(X<2)= 1 - P(X≤1)= 1 - 0.68= 0.32

There is a 32% chance that two or more customers bought a box with an extra donnut.

I hope it helps!

3 0
1 year ago
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inessss [21]

So the given series is "16, 06, 68, 88, __"

Count all the cyclical opening in each of these numbers. For example in 16, there is a one cyclical loop present in it(the one in 6), similarly in 06 it is two(one in zero and one in 6), going ahead, in 68 it is 3(one in 6 and two in 8).

From here on things become simple: hence, the cyclical figures in these equations written down becomes 1,2,3,4,_,3.

Let's now try solving the above sequence, going by the logical reasoning the only number that can fill in the gap should be 4.

4 0
2 years ago
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