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saveliy_v [14]
2 years ago
11

Desiree works 28 hours per week. She has a monthly income of $120 from investments. Desiree also plays in a band one night a wee

k making $200. She has a total annual income of $49,696. Desiree wants to ask her boss for a raise so that next year she can have a total income of $51,880. Assuming the other incomes remain the same, how much of an hourly raise will Desiree need? a. $1.25 b. $1.50 c. $1.75 d. $2.00
Mathematics
2 answers:
Oksi-84 [34.3K]2 years ago
7 0
So hmmm let's see
she has a monthly income of 120 from investments, now, there are 12 months in a year, so her yearly income from investments are 120*12 or
$1440

she plays on a band, and makes 200 a week, now, there are 52 weeks in a year, so her yearly income from band playing is 200 * 52, or
$10400

her total annual income is 49696, now, if we subtract the band and investment income, we'd be left over with only what comes from her job payrate
so 49696 - 1440 - 10400 is 37856

so, she makes from her job, $37856 annually

now, she only works 28 hours weekly, how much is that yearly?   well, 52 weeks in a year, she works 28*52 hours a year, let us divide 37856 by that

37856 ÷ ( 28 * 52)   well, it ends up as 26

so, her hourly payrate is $26 per hour

now, she wants to ask for a raise, to make 51880 annually

well, if we check the difference of 51880 and 49696, that'd leave us with the difference in pay, or the raise annual amount

51880 - 49696 = 2184

ok, so she wants $2184 annually more from her work
how much is that in the hours she works annually?  well 2184 ÷ ( 28 * 52)
aalyn [17]2 years ago
6 0
The answer is B. $1.50
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Answer:

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2 years ago
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Given: NM ∥ XZ Prove: △XYZ ~ △NYM Triangles X Y Z and N Y M are shown. Triangle X Y Z is smaller and sits inside of triangle N Y
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AA

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A trapezoid has an area of 20 cm2 and a height z cm. The lengths of the parallel sides are (2z + 3) cm and (6z – 1) cm. Find the
andriy [413]
Check the picture below.

\bf A=\cfrac{h(a+b)}{2}\quad 
\begin{cases}
A=20\\
a=6z-1\\
b=2z+3\\
h=z
\end{cases}\implies 20=\cfrac{z[(6z-1)~+~(2z+3)]}{2}
\\\\\\
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\\\\\\
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\bf \qquad \qquad \textit{quadratic formula}\\\\
\begin{array}{llccll}
0=&{{ 4}}z^2&{{ +1}}x&{{ -20}}\\
&\uparrow &\uparrow &\uparrow \\
&a&b&c
\end{array} 
\qquad \qquad 
z= \cfrac{ - {{ b}} \pm \sqrt { {{ b}}^2 -4{{ a}}{{ c}}}}{2{{ a}}}
\\\\\\
z=\cfrac{-1\pm\sqrt{1+320}}{8}\implies z=\cfrac{-1\pm\sqrt{321}}{8}\implies z\approx 
\begin{cases}
\boxed{2.1146}\\
-2.3646
\end{cases}

since the height is just a length unit, it can't be -2.3646.

4 0
2 years ago
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