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1 year ago

7

2 box plots. The number line goes from 1 to 11. For Jefferson Middle School recycled cans, the whiskers range from 1 to 9.5, and

the box ranges from 3 to 7. A line divides the box at 4. For West Side Middle School recycled cans, the whiskers range from 1 to 9, and the box ranges from 3 to 8. A line divides the box at 6.
West Side Middle School and Jefferson Middle School recycled cans and kept track of how many pounds of cans each student collected. Use the drop-down menus to answer the questions.

What is the interquartile range of Jefferson Middle School cans recycled?

What is the interquartile range of West Side Middle School cans recycled?

Which school had a greater variability in their middle 50 percent?

2 answers:

Irina18 [472]1 year ago

7 0

Answer:

What is the interquartile range of Jefferson Middle School cans recycled? 4

What is the interquartile range of West Side Middle School cans recycled? 5

Which school had a greater variability in their middle 50 percent? West Side Middle School

Step-by-step explanation:

i just did it:)

E D G E N U I T Y

Alona [7]1 year ago

5 0

Answer:

4

5

West Side Middle School

Step-by-step explanation:

I don't know how to explain it but trust me these answers are correct.

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Use the drop-down menus to complete the statements below to answer this question: Can you determine whether a system of linear e

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The coordinates of a point satisfies the equation of a line if the point lies on the line
If a single point satisfies the equations of two lines, the point is on both lines, so the lines will intersect at that point.
This means that each point where the two lines touch is a solution to the system of equations
This means that if you substitute the x and y values of the point for x and y in the equations, both equations will be true

<h2>Explanation:</h2>

You haven't given any option. However, I have tried to complete this question according to what we know about system of linear equations. Suppose you have the following system of two linear equations in two variables:

$(1) \ y=3+2x \\ \\ (2) \ y=x$

The fist equation is the blue one and the second equation is the red one. Both have been plotted in the first figure below. As you can see, (-3, -3) is the point of intersection and lies on both lines. So this point is a solution of the system of equation and we can also say that it touches both lines. On the other hand, if you substitute the x and y values of the point for x and y in the equations, both equations will be true, that is:

$-3=3+2(-2) \therefore -3=-3 \ True! \\ \\ (2) \ -3=-3 \ True!$

Also, you can have a system with infinitely many solutions as the following:

$(1) \ y+2x=4\\ \\ (2) \ 2y+4x=8$

Here, every point that is solution of the first equation is solution of the second one. That is because both equations are basically the same. If we divide eq (2) by 2, then we get eq (1).

<h2>Learn more:</h2>

System of linear equations in real life problems: brainly.com/question/10412788

#LearnWithBrainly

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1 year ago

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Which subtraction sentences show you how to find 15-7

Alborosie

First you need to divide 7 and 15, and the answer you get is 8, so 8+7=15. 8 will be your answer.

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brian filled 72 glasses with apple juice for a school party if each glass holds 1 cup of juice how many quarts of apple juice di

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1 year ago

Bella has joined a new gym in town. The cost of membership is $25 per month. The after-hours policy at the gym allows her to wor

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The total monthly bill of the gym = $53

The cost of membership of a month = $25

Let 'n' be extra the number of hours Bella worked on.

The cost for working on extra hours = $4

So, we have to determine the equation, Bella worked out after hours.

We will determine the equation by:

(Monthly cost of membership) + ( cost for extra hours $\times$ number of hours extra worked on ) = Total monthly bill received

So, we get

$\$25+(4 \times n) = \$53$

$25+4n = $53 is the required equation.

Therefore, $25+4n = $53 equation can be used to determine how many times Bella worked out after hours.

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1 year ago

Ben and Josh went to the roof of their 40-foot tall high school to throw their math books offthe edge.The initial velocity of Be

Taya2010 [7]

Answer

Josh's textbook reached the ground first

Josh's textbook reached the ground first by a difference of $t=0.6482$

Step-by-step explanation:

Before we proceed let us re write correctly the height equation which in correct form reads:

$h(t)=-16t^2 +v_{o}t+s$ Eqn(1).

Where:

$h(t)$ : is the height range as a function of time

$v_{o}$ : is the initial velocity

$s$ : is the initial heightin feet and is given as 40 feet, thus Eqn(1). becomes:

$h(t)=-16t^2 + v_{o}t + 40$ Eqn(2).

Now let us use the given information and set up our equations for Ben and Josh.

<u>Ben:</u>

We know that $v_{o}=60ft/s$

Thus Eqn. (2) becomes:

$h(t)=-16t^2+60t+40$ Eqn.(3)

<u>Josh:</u>

We know that $v_{o}=48ft/s$

Thus Eqn. (2) becomes:

$h(t)=-16t^2+48t+40$ Eqn. (4).

<em><u>Now since we want to find whose textbook reaches the ground first and by how many seconds we need to solve each equation (i.e. Eqns. (3) and (4)) at </u></em> $h(t)=0$ <em><u>. Now since both are quadratic equations we will solve one showing the full method which can be repeated for the other one. </u></em>

Thus we have for Ben, Eqn. (3) gives:

$h(t)=0-16t^2+60t+40=0$

Using the quadratic expression to find the roots of the quadratic we have:

$t_{1,2}=\frac{-b+/-\sqrt{b^2-4ac} }{2a} \\t_{1,2}=\frac{-60+/-\sqrt{60^2-4(-16)(40)} }{2(-16)} \\t_{1,2}=\frac{-60+/-\sqrt{6160} }{-32} \\t_{1,2}=\frac{15+/-\sqrt{385} }{8}\\\\t_{1}=4.3276 sec\\t_{2}=-0.5776 sec$

Since time can only be positive we reject the $t_{2}$ solution and we keep that Ben's book took $t=4.3276$ seconds to reach the ground.

Similarly solving for Josh we obtain

$t_{1}=3.6794sec\\t_{2}=-0.6794sec$

Thus again we reject the negative and keep the positive solution, so Josh's book took $t=3.6794$ seconds to reach the ground.

Then we can find the difference between Ben and Josh times as

$t_{Ben}-t_{Josh}= 4.3276 - 3.6794 = 0.6482$

So to answer the original question:

<em>Whose textbook reaches the ground first and by how many seconds?</em>

Josh's textbook reached the ground first
Josh's textbook reached the ground first by a difference of $t=0.6482$

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1 year ago