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Delicious77 [7]
2 years ago
5

When dividing with polynomials, the goal is to determine how many times the dividend divides evenly into the?

Mathematics
1 answer:
kkurt [141]2 years ago
5 0
Whether dividing constant terms or polynomials, we always have definitive terms when it comes to division. Suppose we say, 10x divided by 2. The dividend is the 10x and the divisor is the 2. In other words, the dividend is the number to be divided by the divisor, to obtain the answer called the quotient.

When dividing polynomials, your main goal is to be able to divide the dividend evenly into the <em>divisor</em>. For example, we divide x²+2x+1 by x+1. The first thing you're going to focus is, what term will completely divide the first term of the polynomial? That would be x. Why? Because when you multiply x with x+1, the product is x²+x. When you subtract this from the polynomial, the x² will cancel out. All you have to do is subtract x from 2x, yielding x. Then, you carry down the last term of the equation: +1. You do the steps again. The term that will completely divide x+1 by x+1 is 1. When you subtract the two, you will come up with zero. That means there is no remainder. The polynomial is divisible by the divisor. 
                          x + 1
                        ------------------------------------
                  x+1| x²+2x+1
                        - x²+x
                         ----------------------
                                 x +1
                               - x + 
                             ------------
                                    0
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After traveling for 4 hours and 1800 miles, an airplane begins a steady descent. When it begins descending, its altitude (height
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Part 1)  Descending Rate = -2,000 ft/min

Part 2)  Starting altitude value is 33,000 ft

Part 3)  The linear equation for the plane's altitude (y) as a function of time (x) is:  y=-2000\,\frac{ft}{min} \,x\,+\,33000\,ft

Part 4)  The information not used for the equation is that the plane was travelling for 4 hours to cover 1800 miles before starting the descent

Step-by-step explanation:

Part 1)

The rate at which the airplane descends is given by the difference between final and initial altitude (17,000 ft-33,000 ft) divided the elapsed time (8 minutes):

Descending\,\,Rate\,= \frac{17000-33000}{8} \,\,\frac{ft}{min}=\frac{-16000}{8} \,\,\frac{ft}{min}=-\,2000\,\,\frac{ft}{min}

Part 2)

When graphing the descent (that is the plane's altitude as a function of time), the starting value for the altitude should be 33,000 ft

Part 3)

We can build the equation of the plane's altitude as a function of time in slope y-intercept form y = m x + b

by noticing that the slope "m" stands for the rate of descent that we found in part 1), and then using the information that at time zero (when the plane starts its descent), its altitude is 33000 ft:

y=m\,x\,+\,b\\y=-2000\,\frac{ft}{min} \,x\,+\,b\\33000=-2000\,\frac{ft}{min} \,(0)\,+\,b\\33000=b

with this information about the intercept "b", we can write the final expression for the plane's altitude as a function of time during its descent as:

y=-2000\,\frac{ft}{min} \,x\,+\,33000\,ft

Part 4)

The information that was not used to write the descent equation was the initial details about how long the plane traveled (4 hours) and for 1800 miles.

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