Answer:
69.1
Step-by-step explanation:
<em>Mean height of 14 students = 69.0 inches</em>
<em>Mean = sum of data/number of data</em>
<em>69 = sum of data/14</em>
<em>sum of data = 966</em>
<u>FOR NEW MEAN:</u>
<em>Height of additional student = 70.5</em>
Mean = sum of data/ number of data
Mean = 966+70.5/14+1
Mean = 1036.5/15
Mean = 69.1
Therefore, the mean height of the 15 students in the class is 69.1
Whatever% of anything is just (whatever/100) * anything.
so 56% of 75 mates like it, how much is 56% of 75? well is just (56/100) * 75, namely 42.
and 80% of 60 relatives like it as well, how much is 80% of 60? well, is just (80/100) * 60, namely 48.
how many more? well, 48 - 42.
Answer:
Choice A: there is insufficient evidence to conclude that the mean for the fiber content is less than 2.5 gms.
Step-by-step explanation:
From the graphs given the more appropriate is one sample t- test
One sample t- test is used and the results are
Hypothesis Test Fiber
Sample Mean 2.62
Sample St. Dev 3.492
Degrees of Freedom 24
t- test statistic 0.1718
p- value 0.5675
the critical region for this test at ∝= 0.05 is t < -1.711
There is not enough evidence to reject the null hypothesis.
Since the calculated t= 0.1718 does not fall in the critical region the null hypothesis is accepted that the mean fiber content is not less than 2.5 grams.T
From the dot plot, we have that 90.91% of the students have 5 or more vowels in their first and last names.
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The dot plot states that:
- 2 students have 4 vowels in their first and last name.
- 3 students have 5 vowels.
- 8 students have 6 vowels.
- 9 students have 7 vowels.
Then:
- Total of 2 + 3 + 8 + 9 = 22 students.
- 3 + 8 + 9 = 20 have or more vowels.
90.91% of the students have 5 or more vowels in their first and last names.
A similar problem is given at brainly.com/question/14354536
