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Ierofanga [76]
1 year ago
6

Consider the following differential equation. (A computer algebra system is recommended.) (1 + t2)y' + 4ty = (1 + t2)−2 (a) Draw

a direction field for the given differential equation.

Mathematics
1 answer:
alina1380 [7]1 year ago
3 0

Answer:

Step-by-step explanation:

a. Draw a direction field for the given differential equation

b. Based on the inspection of the direction field, describe ow solutions behave for large t.

The solution appear oscillatory

All solutions seems to converge to the function y0(t)=4

All solutions seems to converge to the function y0(t)=0

All solutions seems to seems to eventually have negative slopes a and hence decrease without bound

All solutions seems to seems to eventually have positive slopes a and hence increase without bound

C

As t-infinity

All solutions seems to seems to eventually have positive slopes a and hence decrease without bound

All solutions seems to converge to the function y0(t)=0

All solutions seems to seems to eventually have negative slopes a and hence decrease without bound

All solutions seems to converge to the function y0(t)=4

The solution are oscillatory

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Express Rs 1.50 as a percentage of 200 cents
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Consider the midterm and final for a statistics class. Suppose 13% of students earned an A on the midterm. Of those students who
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Answer:

There is a 38.97% probability that this student earned an A on the midterm.

Step-by-step explanation:

The first step is that we have to find the percentage of students who got an A on the final exam.

Suppose 13% students earned an A on the midterm. Of those students who earned an A on the midterm, 47% received an A on the final, and 11% of the students who earned lower than an A on the midterm received an A on the final.

This means that

Of the 13% of students who earned an A on the midterm, 47% received an A on the final. Also, of the 87% who did not earn an A on the midterm, 11% received an A on the final.

So, the percentage of students who got an A on the final exam is

P_{A} = 0.13(0.47) + 0.87(0.11) = 0.1568

To find the probability that this student earned an A on the final test also earned on the midterm, we divide the percentage of students who got an A on both tests by the percentage of students who got an A on the final test.

The percentage of students who got an A on both tests is:

P_{AA} = 0.13(0.47) = 0.0611

The probability that the student also earned an A on the midterm is

P = \frac{P_{AA}}{P_{A}} = \frac{0.0611}{0.1568} = 0.3897

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5 0
1 year ago
If ray NP bisects <MNQ, m<MNQ=(8x+12)°, m<PNQ=78°, and m<RNM=(3y-9)°, find the value of x and y
aksik [14]

Step 1

<u>Find the measure of angle x</u>

we know that

If ray NP bisects <MNQ

then

m<MNQ=m<PNM+m<PNQ ------> equation A

and

m<PNM=m<PNQ -------> equation B

we have that

m<MNQ=(8x+12)°

m<PNQ=78°

so

substitute in equation A

(8x+12)=78+78-------> 8x+12=156------> 8x=156-12

8x=144------> x=18°

Step 2

<u>Find the measure of angle y</u>

we have

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m<PNM=78°

so

3y-9=78------> 3y=87------> y=29°

therefore

<u>the answer is</u>

the measure of x is 18° and the measure of y is 29°


7 0
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