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Harlamova29_29 [7]
2 years ago
6

Two pumps connected in parallel fail independently of one another on any given day. The probability that only the older pump wil

l fail is .10, and the probability that only the newer pump will fail is .05. What is the probability that the pump- ing system will fail on any given day (which happens if both pumps fail)?
Mathematics
1 answer:
Bogdan [553]2 years ago
8 0

Answer : Probability that the pumping system will fail on any given day = 0.005

Explanation:

Probability that only older pump fail = P(A) = 0.10

Probability that only newer pump fail = P(B) = 0.05

Since they are independent events ,

then the conditions will be

P(A∩B) = P(A). P(B)

             = 0.10 ×0.05

             =  0.005

Hence, the probability will fail on any given day = 0.005

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Suppose that two people standing 5 miles apart both see the burst from a fireworks display. After a period of time, the first pe
RideAnS [48]

Answer:

the fireworks display occured at x = 1,266,650 ft

Step-by-step explanation:

We are told that sound travels at 1100 feet per second

We will use the general equation for an hyperbola given by;

(y²/a²) - (x²/b²) = 1

We assume that the longer axis for the hyperbola is on the y axis.

In this problem, the total distance traveled by the sound is 1100 ft per second and we can find the value of "a" as:

2a = 1100

a = 1100/2 = 550

Also, since both people are 5 miles apart, we can find the value of c like this:

2c = 2(5)

So,c = 5 miles

Since the distance of sound was given in ft. Thus;

Lets convert 5 miles to ft.

1 mile = 5280 ft

Thus; 5 miles = 5 x 5280 = 26,400 ft

Now, we can find b² from;

b² = c² - a²

b² = 26400² - 550²

b² = 696960000 - 302500

b² = 696657500

Thus, plugging in the relevant values to obtain;

(y²/302500) - (x²/696657500) = 1

In this case we want to find the value of x when y = 5miles = 26400 ft

solving for x we have:

(26400²/302500) - (x²/696657500) = 1

This leads to;

2304 - (x²/696657500) = 1

Thus;

2304 - 1 = (x²/696657500)

2303 x 696657500 = x²

x² = 1604402222500

x = √1604402222500

x = 1,266,650 ft

5 0
2 years ago
A small town in Louisiana is over 300 years old. Over the years as the town grew, the property owners established the property l
irga5000 [103]
SHAPE  A

Shape A can be split into two shapes as shown in the diagram below. One is a rectangle and the other is an isosceles triangle. The dimension of the rectangle is 80×180 but we do not know the base of the triangle.

Area of rectangle = 80×180 = 14400

Base of rectangle can be worked out using the Pythagoras theorem
x= \sqrt{65^{2}- 60^{2} } =25
the base of the triangle = 2×25 = 50

Area of rectangle = 1/2(base)(height) = 0.5×50×60 = 1950

Total area of shape A = 1950 + 14400 = 16350
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Total perimeter of shape A = 80+80+180+65+65 = 470

SHAPE B

We split shape B into a parallelogram and a trapezium
Area of parallelogram = base × height = 250 × 30 = 7500
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Total area = 5600 + 7500 = 13100
Tax = 13100÷100 = $131

Perimeter  = 250+250+35+35+100+40+80 = 790

SHAPE C

Shape C is an isosceles shape which allows us to split side bc into 100÷2=50. The diagram is shown in the third diagram.

Quadrilateral PODY = Quadrilaterla AXPO
Side CY = \sqrt{107^{2}- 100^{2} } =38.1
Side PY = 50+38.1 = 88.1
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Area of PODY = \frac{100+23}{2}*88.1=5418.15
Area of DCY = \frac{1}{2}*38.1*100=1905
Area of DCPO = 5418.15-1905 = 3513.15
Area of ABCD = 3513.15×2 = 7026.3

Tax = 7026.3÷100 = $70.263

Perimeter = 117+117+107+107+100 = 548


SHAPE D

Shape D can be split into a triangle and a trapezium as shown in the fourth diagram below

Area of triangle = \frac{1}{2}*150*300=22500
Area of trapezium = \frac{500+300}{2}*400=160000
Total area = 22500 + 160000 = 182500

Tax = 182500÷100 = $1825

Perimeter = 280+165+406+500+425 = 1776

4 0
2 years ago
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