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Harlamova29_29 [7]
2 years ago
6

Two pumps connected in parallel fail independently of one another on any given day. The probability that only the older pump wil

l fail is .10, and the probability that only the newer pump will fail is .05. What is the probability that the pump- ing system will fail on any given day (which happens if both pumps fail)?
Mathematics
1 answer:
Bogdan [553]2 years ago
8 0

Answer : Probability that the pumping system will fail on any given day = 0.005

Explanation:

Probability that only older pump fail = P(A) = 0.10

Probability that only newer pump fail = P(B) = 0.05

Since they are independent events ,

then the conditions will be

P(A∩B) = P(A). P(B)

             = 0.10 ×0.05

             =  0.005

Hence, the probability will fail on any given day = 0.005

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The population of lengths of aluminum-coated steel sheets is normally distributed with a mean of 30.05 inches and a standard dev
Vladimir [108]

Answer:

Probability that the average length of a sheet is between 30.25 and 30.35 inches long is 0.0214 .

Step-by-step explanation:

We are given that the population of lengths of aluminum-coated steel sheets is normally distributed with a mean of 30.05 inches and a standard deviation of 0.2 inches.

Also, a sample of four metal sheets is randomly selected from a batch.

Let X bar = Average length of a sheet

The z score probability distribution for average length is given by;

                Z = \frac{Xbar-\mu}{\frac{\sigma}{\sqrt{n} } } ~ N(0,1)

where, \mu = population mean = 30.05 inches

           \sigma   = standard deviation = 0.2 inches

             n = sample of sheets = 4

So, Probability that average length of a sheet is between 30.25 and 30.35 inches long is given by = P(30.25 inches < X bar < 30.35 inches)

P(30.25 inches < X bar < 30.35 inches)  = P(X bar < 30.35) - P(X bar <= 30.25)

P(X bar < 30.35) = P( \frac{Xbar-\mu}{\frac{\sigma}{\sqrt{n} } } < \frac{30.35-30.05}{\frac{0.2}{\sqrt{4} } } ) = P(Z < 3) = 0.99865

 P(X bar <= 30.25) = P( \frac{Xbar-\mu}{\frac{\sigma}{\sqrt{n} } } <= \frac{30.25-30.05}{\frac{0.2}{\sqrt{4} } } ) = P(Z <= 2) = 0.97725

Therefore, P(30.25 inches < X bar < 30.35 inches)  = 0.99865 - 0.97725

                                                                                       = 0.0214

                                       

7 0
2 years ago
During the first seconds after takeoff, a rocket traveled 208 kilometers in 50 minutes at a constant rate suppose a penny is dro
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the penny travels at a faster rate by 56.4 kilometers

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rocket = 208 in 50 min

208/5 = 41.6 *6 = 249.6 in 1 hour

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Westkost [7]

Answer:

Miguel start to swim when Ario has traveled 4.4 m.

Step-by-step explanation:

The total lenght of the pool is 25.

Since both of them standing 3 m from one side of the pool, then, the total distance both need to cover is 25-3 m= 22 m.

Assume that the distance traveled by Ario before Miguel start to swin is x. That means, the remaining distance to Ario (to cover the total size of the pool) is 22-x.

Then, in acoordance to the problem, the ratio between these two distances must be equal to 1/4.

That is,

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Answer:

The answer will be x = 8

Step-by-step explanation:

the last step: 5x = 40

you divide 5 both sides: 5x/5 = 40/5

then you got your answer: x = 8

4 0
2 years ago
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Answer: D

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