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1 year ago

7

In some languages, every consonant must be followed by a vowel. How many seven-letter ‟words” can be made from the Hawaiian word

MAKAALA if each consonant must be followed by a vowel?

1 answer:

emmasim [6.3K]1 year ago

7 0

Answer:

One. Kamala.

Step-by-step explanation:

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The graph of y=3x^2-3x-1 is shown. Use the graph to find estimates for the solutions of i)3x^2-3x+2=2 ii) 3x^2-3x-1=x+1

AlexFokin [52]

Answer:

i) (0, 2) and (1, 2), ii) (0.333, 1.333) and (1, 2).

Step-by-step explanation:

i) Let be $y=3\cdot x^{2}-3\cdot x -1$ , if $3\cdot x^{2}-3\cdot x +2 = 2$ , which is equivalent to the following system of equations:

$y = 3\cdot x^{2}-3\cdot x +2$

$y = 2$

Now, this system is now represented by means of a graphing tool and whose outcome is attached below. There are two solutions: (0, 2) and (1, 2)

ii) Let be $y=3\cdot x^{2}-3\cdot x -1$ , if $3\cdot x^{2}-3\cdot x +2 = x+1$ , which is equivalent to the following system of equations:

$y = 3\cdot x^{2}-3\cdot x +2$

$y = x+1$

Now, this system is now represented by means of a graphing tool and whose outcome is attached below. There are two solutions: (0.333, 1.333) and (1, 2)

7 0

2 years ago

A test tube contains 25 bacteria, 5 of which are can stay alive for atleast 30 days, 10 of which will die in their second day. 1

boyakko [2]

Answer:

c. $\frac{1}{5}$

Step-by-step explanation:

Given,

Number of bacterias who alive for at least 30 days = 5,

Bacterias who alive for 2 days = 10,

Died bacterias = 10,

Total bacterias = 5 + 10 + 10 = 25,

Ways of choosing a bacteria = $^{25}C_1$ = $\frac{25!}{1! 24!}$ = 25,

While, ways of choosing of a bacteria who will live after 1 week = $^5C_1$ = $\frac{5!}{1!4!}$ = 5,

Hence, the probability it will still be alive after one week = $\frac{5}{25}$ = $\frac{1}{5}$

OPTION C is correct.

3 0

2 years ago

The rectangle below has an area of 6n^4+20n^3+14n^26n 4 +20n 3 +14n 2 6, n, start superscript, 4, end superscript, plus, 20, n,

Sindrei [870]

Given:

Area of rectangle = $6n^4+20n^3+14n^2$

Width of the rectangle is equal to the greatest common monomial factor of $6n^4, 20n^3,14n^2$ .

To find:

Length and width of the rectangle.

Solution:

Width of the rectangle is equal to the greatest common monomial factor of $6n^4, 20n^3,14n^2$ is

$6n^4=2\times 3\times n\times n\times n\times n$

$20n^3=2\times 2\times 5\times n\times n\times n$

$14n^2=2\times 7\times n\times n$

Now,

$GCF(6n^4, 20n^3,14n^2)=2\times n\times n=2n^2$

So, width of the rectangle is $2n^2$ .

Area of rectangle is

$Area=6n^4+20n^3+14n^2$

Taking out GCF, we get

$Area=2n^2(3n^2+10n+7)$

We know that, area of a rectangle is the product of its length and width.

Since, width of the rectangle is $2n^2$ , therefore length of the rectangle is $(3n^2+10n+7)$ .

5 0

2 years ago

A 3-gallon tub of ice cream yields about 90 scoops of ice cream. There are roughly 3785 cubic centimeters in 1 gallon. Determine

ASHA 777 [7]

Answer:

The radius of the scoop is r = 3.1 cm

Step-by-step explanation:

Since 3 gallons yields 90 scoops, and 1 gallon = 3785 cm³.

3 gallons = 3 × 3785 cm³ = 11355 cm³

So we have 11355 cm³ in 3 gallons which is also the volume of 90 scoops.

Since 90 scoops = 11355 cm³, then

1 scoop = 11355 cm³/90 = 126.2 cm³

Now, if each scoop is a sphere, the volume is given by V = 4πr³/3 where r is the radius of the scoop. Since we need to find the radius of the scoop, r, making r subject of the formula, we have

r = ∛(3V/4π)

Substituting V = 126.2 cm³, we have

r = ∛(3× 126.2 cm³/4π)

= ∛(378.6 cm³/12.57)

= ∛30.13 cm³

= 3.1 cm

So, the radius of the scoop is r = 3.1 cm

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2 years ago

There are 10 red counters and x blue counters in a bag. 2 counters are removed fron the bag. the probability that both counters

frutty [35]

Step-by-step explanation:

10 red 6 blue so 16 altogether.

apologies if I'm wrong

8 0

2 years ago