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Margarita [4]
2 years ago
13

An operation manager at an electronics company wants to test their amplifiers. The design engineer claims they have a mean outpu

t of 451451 watts with a variance of 144144. What is the probability that the mean amplifier output would be greater than 449.8449.8 watts in a sample of 7676 amplifiers if the claim is true?Round your answer to four decimal places.
Mathematics
1 answer:
PtichkaEL [24]2 years ago
7 0

Answer:

The probability that the mean amplifier output would be greater than 449.8 watts in a sample of 76 amplifiers is 0.8078.

Step-by-step explanation:

According to the Central Limit Theorem if an unknown population is selected with mean μ and standard deviation σ and appropriately huge random samples (n > 30) are selected from this population with replacement, then the distribution of the sample means will be approximately normally.  

Then, the mean of the sample means is given by,

\mu_{\bar x}=\mu

And the standard deviation of the sample means is given by,

\sigma_{\bar x}=\frac{\sigma}{\sqrt{n}}

The information provided is as follows:

\mu=451\\\sigma^{2}=144\\n=76\\\bar x=449.8

Compute the probability that the mean amplifier output would be greater than 449.8 watts in a sample of 76 amplifiers as follows:

P(\bar X>449.8)=P(\frac{\bar X-\mu_{\bar x}}{\sigma_{\bar x}}>\frac{449.8-451}{\sqrt{144/76}})\\\\=P(Z>-0.87)\\\\=P(Z

*Use a <em>z</em>-table.

Thus, the probability that the mean amplifier output would be greater than 449.8 watts in a sample of 76 amplifiers is 0.8078.

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A computer is normally $899 but is discounted to $799. What percent of the original price does Shawn pay?
Oksi-84 [34.3K]
<span>A computer is normally $899 but is discounted to $799.
Question: What percent of the original price does Shawn pay?
=> 799 dollars is the discounted price
=> 899 dollars is the original price
=> 899 – 799 = 100 dollars – the discount price that was deducted to the original price.
Solution
=> 100 / 899 = 0.11
=> 0.11 * 100% = 11%
Thus, the computer has a discount of 11%.</span>



4 0
2 years ago
The table below represents Gerry's trip to school and back home. If the total time is 45 minutes, how far does Gerry live from s
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Answer: X/8 + X/16 = 3/4

Step-by-step explanation:

you’re just dividing the distance by the rate you are going.

5 0
1 year ago
Read 2 more answers
Let Y denote a geometric random variable with probability of success p. a Show that for a positive integer a, P(Y &gt; a) = qa .
lakkis [162]

Answer:

a) For this case we can find the cumulative distribution function first:

F(k) = P(Y \leq k) = \sum_{k'=1}^k P(Y =k')= \sum_{k'=1}^k p(1-p)^{k'-1}= 1-(1-p)^k

So then by the complement rule we have this:

P(Y>a) = 1-F(a)= 1- [1-(1-p)^a]= 1-1 +(1-p)^a = (1-p)^a = q^a

b) P(Y>a)= q^a

P(Y>b) = q^b

So then we have this using independence:

P(Y> a+b) = q^{a+b}

We want to find the following probability:

P(Y> a+b |Y>a)

Using the definition of conditional probability we got:

P(Y> a+b |Y>a)= \frac{P(Y> a+b \cap Y>a)}{P(Y>a)} = \frac{P(Y>a+b)}{P(Y>a)} = \frac{q^{a+b}}{q^a} = q^b = P(Y>b)

And we see that if a = 2 and b=5 we have:

P(Y> 2+5 | Y>2) = P(Y>5)

c) For this case we use independent identical and with the same distribution experiments.

And the result for part b makes sense since we are interest in find the probability that the random variable of interest would be higher than an specified value given another condition with a value lower or equal.

Step-by-step explanation:

Previous concepts

The geometric distribution represents "the number of failures before you get a success in a series of Bernoulli trials. This discrete probability distribution is represented by the probability density function:"

P(X=x)=(1-p)^{x-1} p

If we define the random of variable Y we know that:

Y\sim Geo (1-p)

Part a

For this case we can find the cumulative distribution function first:

F(k) = P(Y \leq k) = \sum_{k'=1}^k P(Y =k')= \sum_{k'=1}^k p(1-p)^{k'-1}= 1-(1-p)^k

So then by the complement rule we have this:

P(Y>a) = 1-F(a)= 1- [1-(1-p)^a]= 1-1 +(1-p)^a = (1-p)^a = q^a

Part b

For this case we can use the result from part a to conclude that:

P(Y>a)= q^a

P(Y>b) = q^b

So then we have this assuming independence:

P(Y> a+b) = q^{a+b}

We want to find the following probability:

P(Y> a+b |Y>a)

Using the definition of conditional probability we got:

P(Y> a+b |Y>a)= \frac{P(Y> a+b \cap Y>a)}{P(Y>a)} = \frac{P(Y>a+b)}{P(Y>a)} = \frac{q^{a+b}}{q^a} = q^b = P(Y>b)

And we see that if a = 2 and b=5 we have:

P(Y> 2+5 | Y>2) = P(Y>5)

Part c

For this case we use independent identical and with the same distribution experiments.

And the result for part b makes sense since we are interest in find the probability that the random variable of interest would be higher than an specified value given another condition with a value lower or equal.

8 0
2 years ago
You design the wooden poster frame and paint the front surface a. write a polynomial that represents the area of the wood you pa
Brilliant_brown [7]
A= 12x^{2} +60x+48 - 320 or A= 12x^{2} +60x - 272
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7 0
2 years ago
On average, Betsy read 1 page of her book every 1.5 minutes. Her book has 116 pages. Raymond starts a 94- page book on Saturday
natka813 [3]

Answer:

14 minutes

Step-by-step explanation:

given,

given,

Betsy time taken to read one page = 1.5 minutes

Number of pages in the Betsy book = 116 pages

number of pages in Raymond Book = 94 pages

time taken by the Raymond  to read = 11.38 - 8.30

                                                             = 3.08 hrs

time taken by Raymond = 188 minutes

time taken by Betsy to read book = 1.5 x 116

                                                         = 174 minutes

Raymond take more time than Betsy by  = 188 - 174

                                                                   = 14 minutes

Raymond take 14 minute more than Betsy

4 0
2 years ago
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