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Arturiano [62]
2 years ago
15

A store uses the expression –2p + 50 to model the number of backpacks it sells per day, where the price, p, can be anywhere from

$9 to $15. Which price gives the store the maximum amount of revenue, and what is the maximum revenue?
(Revenue = price x number of backpacks.)

A. $9.00 per backpack gives the maximum revenue; the maximum revenue is $32.00.
B. $12.00 per backpack gives the maximum revenue; the maximum revenue is $312.00.
C. $12.50 per backpack gives the maximum revenue; the maximum revenue is $312.50.
D. $15.00 per backpack gives the maximum revenue; the maximum revenue is $20.00.
Mathematics
2 answers:
Anettt [7]2 years ago
8 0
Letter C has the highest revenue so we will just have to check if it is correct.

-2(12.50)+50 = 25
Revenue = <span>price x number of backpacks
Revenue = 25 x $12.50
Revenue = $312.50

So, letter C is the correct answer.</span>
kirill [66]2 years ago
8 0

Answer:

$12.50 per backpack gives the maximum revenue; the maximum revenue is $312.50.

Step-by-step explanation:

It's c, i got it right on edge

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You save $5,000.00 and invest 60% of it in stocks while leaving the rest in a savings account earning a 4.9% APR. The stock incr
Angelina_Jolie [31]

Answer:

5,340

Step-by-step explanation:

Hi there:)

Amount invested in stock

=5000×0.6=3000

Amount invested in a saving account

5000-3000=2000


The stock increases 9% in the first year

3,000×(1+0.09)=3,270

and loses 4% of its value the second year

3,270×(1−0.04)=3,139.2

Amount of a saving account after two years

2,000×(1+0.049)^(2)=2,200.8


the total amount gained during the 2 years

3,139.2+2,200.8=5,340...answer


Hope it helps




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2 years ago
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Application of the least squares method results in values of the y-intercept and the slope that minimizes the sum of the squared
vaieri [72.5K]

Answer:

c. observed values of the independent variable and the predicted values of the independent variable

Step-by-step explanation:

This helps us, for example, find the values of y in a y = f(x) equation. y is dependent of x. So x is the independent variable and y the dependent. Obviously, this system is used for way more complex equations, in which is hard to find an actual pattern for y, so we use this method to compare the predicted values of y to the observed.

The correct answer is:

c. observed values of the independent variable and the predicted values of the independent variable

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If you vertically stretch the exponential function f(x) = 2X by a factor of 5, what
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The answer to your question is A
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"Majesty Video Production Inc. wants the mean length of its advertisements to be 30 seconds. Assume the distribution of ad lengt
Westkost [7]

Answer:

a) \bar X \sim N(\mu=30, \frac{2}{\sqrt{16}})

b) Se=\frac{\sigma}{\sqrt{n}}=\frac{2}{\sqrt{16}}=0.5

c) P(\bar X >31.25)=0.006=0.6\%

d) P(\bar X >28.25)=0.9997=99.97\%

e) P(28.25

Step-by-step explanation:

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".  

The central limit theorem states that "if we have a population with mean μ and standard deviation σ and take sufficiently large random samples from the population with replacement, then the distribution of the sample means will be approximately normally distributed. This will hold true regardless of whether the source population is normal or skewed, provided the sample size is sufficiently large".

Let X the random variabl length of advertisements produced by Majesty Video Production Inc. We know from the problem that the distribution for the random variable X is given by:

X\sim N(\mu =30,\sigma =2)

We take a sample of n=16 . That represent the sample size.

a. What can we say about the shape of the distribution of the sample mean time?

From the central limit theorem we know that the distribution for the sample mean \bar X is also normal and is given by:

\bar X \sim N(\mu, \frac{\sigma}{\sqrt{n}})

\bar X \sim N(\mu=30, \frac{2}{\sqrt{16}})

b. What is the standard error of the mean time?

The standard error is given by this formula:

Se=\frac{\sigma}{\sqrt{n}}=\frac{2}{\sqrt{16}}=0.5

c. What percent of the sample means will be greater than 31.25 seconds?

In order to answer this question we can use the z score in order to find the probabilities, the formula given by:

z=\frac{\bar X- \mu}{\frac{\sigma}{\sqrt{n}}}

And we want to find this probability:

P(\bar X >31.25)=1-P(\bar X

d. What percent of the sample means will be greater than 28.25 seconds?

In order to answer this question we can use the z score in order to find the probabilities, the formula is given by:

z=\frac{\bar X- \mu}{\frac{\sigma}{\sqrt{n}}}

And we want to find this probability:

P(\bar X >28.25)=1-P(\bar X

e. What percent of the sample means will be greater than 28.25 but less than 31.25 seconds?"

We want this probability:

P(28.25

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2 years ago
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Tanzania [10]

We can solve this problem by correctly analyzing the location of the points.

If the center of rotation is a point outside the triangle, then this would mean that there would be quadrant shift (revolution) of the whole triangle itself. Hence this would mean that the resulting triangle will not touch the pre-image at any point at all.

If the center of rotation is a point on the perimeter of the triangle, this would also result in a quadrant shift (revolution) or movement of the triangle.

Now if the center of rotation is a point inside the triangle, then this would be a simple rotation on its own quadrant hence the resulting image will touch the pre-image at more than one point. Hence the correct points are:

<span>point D and point E</span>

8 0
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