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2 years ago

If an organism had 200 atoms of carbon-14 at death, how many atoms will be present after 14,325 years

Mathematics

2 answers:

xxTIMURxx [149]2 years ago

7 0

35.36 of the carbon-14 will still remain. Hope this helps!:)

Natali [406]2 years ago

3 0

Answer:

If an organism had 200 atoms of carbon-14 at death, how many atoms will be present after 14,325 years? Round the answer to the nearest hundredth.

35.36

atoms

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Suppose a research paper states that the distribution of the daily sea-ice advance/retreat from each sensor is similar and is ap

Luda [366]

Answer:

The value of the parameter is λ is 0.03553357

Step-by-step explanation:

Consider the provided function.

$f(x) = 0.5\lambda e^{-\lambda |x|}$ for −∞ < x < ∞.

It is given that standard deviation is given as 39.8 km.

Now we need to calculate the value of parameter λ.

The general formula for the probability density function of the double exponential distribution is: $f(x)=\frac{e^{-|\frac{x-\mu}{\beta}|}}{2\beta}$

Where μ is the location parameter and β is the scale parameter.

Compare the provided equation with the above formula we get.

$\lambda=\frac{1}{\beta}$ and μ = 0.

Standard deviation = √2β

$S.D=\sqrt{2} \beta\\\beta=\frac{39.8}{\sqrt{2}}\\\beta=28.1424$

Now substitute the value of β in $\lambda=\frac{1}{\beta}$ .

$\lambda=\frac{1}{28.1424}=0.03553357$

Hence, the value of the parameter is λ is 0.03553357

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2 years ago

A tire manufacturer has a 60,000 mile warranty for tread life. The company wants to make sure the average tire lasts longer than

aleksandrvk [35]

Answer:

The alternative hypothesis being tested in this example is that the tire life is of more than 60,000 miles, that is:

$H_1: \mu > 60,000$

Step-by-step explanation:

A tire manufacturer has a 60,000 mile warranty for tread life. The company wants to make sure the average tire lasts longer than 60,000 miles.

At the null hypothesis, we test if the tire life is of at most 60,000 miles, that is:

$H_0: \mu \leq 60,000$

At the alternative hypothesis, we test if the tire life is of more than 60,000 miles, that is:

$H_1: \mu > 60,000$

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2 years ago

You and a group of friends are going to a five-day outdoor music festival during spring break. You hope it does not rain during

KIM [24]

Answer:

The probability of not rain during the entire festival is 0.19

Step-by-step explanation:

The Complement Rule states that the sum of the probabilities of an event and its complement must equal 1.

In this case we have the probability of raining of each day, we need the probability of NOT raining.

First day= 45% chance of rain, the complement is 55%

Second day 55% chance of rain, the complement is 45%

Third day a 10% chance of rain, the complement is 90%

Fourth day a 10% chance of rain, the complement is 90%

Fifth day 5% chance of rain, the complement is 95%

To get the probability of NOT raining in the entire festival is the multiplication of all the complements.

P(not raining) = 0.55 x 0.45 x 0.90 x 0.90 x 0.95= 0.19

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2 years ago

Explain whether 13t−3t is equivalent to 3t−13t. Support your answer by evaluating the expressions for t=2.

djverab [1.8K]

Answer:

Not equivalent

Step-by-step explanation:

13t - 3t = (13 - 3)t = 10t
3t - 13t = (3 - 13)t = -10t
10t ≠ -10t

They are not equivalent

13t - 3t = 13*2 - 3*2 = 26 - 6 = 20
3t - 13t = 3*2 - 13*2 = 6 - 26 = -20

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1 year ago

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Kendra made a scaled copy of the following square. She used a scale factor less than 111. What could be the side length of the s

ololo11 [35]

Answer:

2 units

1/4 unit

5 units

Step-by-step explanation:

Khan ^w^'

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2 years ago