Answer:
Given:
length of the wire = 0.20 meters
magnetic field strength = 0.45 newtons/amperes meter
speed = 10.0 meters per second
emf = B * l * v
B = flux density ; l = length of the wire ; v = velocity of the conductor
emf = 0.45 newtons / ampere meter * 0.20 meters * 10.0 meters/seconds
emf = 0.90 volts
The emf produced is 0.90 volts.
Step-by-step explanation:
angle AOB = 132 and is also the sum of angles AOD and
DOB. Hence
angle AOD + angle DOB = 132° ---> 1
angle COD = 141 and is also the sum of angles COB and BOD. Hence
angle COB + angle DOB = 141° ---> 2
Now we add the left sides together and the right sides of equations 1 and 2
together to form a new equation.
angle AOD + angle DOB + angle COB + angle DOB = 132 + 141 ---> 3
We should also note that:
angle AOD + angle DOB + angle COB = 180°
Therefore substituting angle AOD + angle DOB + angle COB in equation 3 by 180
and solving for angle DOB:
180 + angle DOB = 132 + 141
angle DOB = 273 - 180 = 93°
Sasha's family traveled 11,944 miles.
(( 4 round trips = 8 trips ))
(( 1493 x 8 ))
Hope this helps!
Answer:
A. y = 3sin(x-2) + 1
Step-by-step explanation:
Answer:
a) 0.88
b) 0.35
c) 0.0144
d) 0.2084
e) 0.7916
Step-by-step explanation:
a) The probability of a peanut being brown is 12/100 = 0.12. Hence the probability of it not being brown is 1-0.12 = 0.88
b) 12% of peanuts are brown, 23% are blue. So 35% are either blue or brown. The probability of a peanut being blue or brown is, therefore 35/100 = 0.35.
c) 12% of peanuts are red, so the probability of a peanut being red is 12/100 = 0.12. In order to calculate the probability of 2 peanuts being both red, we can assume that the proportion doesnt change dramatically after removing one peanut (because the number of peanuts is absurdly high. We can assume that we are replenishing the peanuts). To calculate the probability of 2 peanuts being both red, we need to power 0.12 by 2, hence the probability is 0.12² = 0.0144.
d) Again, we will assume that the probability doesnt change, because we replenish. The probability of a peanut being blue is 0.23. The probability of it not being blue is 0.77, so the probability of 6 peanuts not being blue is obtained from powering 0.77 by 6, hence it is 0.77⁶ = 0.2084
e) The event 'at least one peanut is blue' is te complementary event of 'none peanuts are blue', so the probability of this event is 1- 0.2084 = 0.7916
