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mestny [16]
2 years ago
7

Two numbers are called relatively prime if their greatest common divisor is $1$. Grogg's favorite number is the product of the i

ntegers from $1$ to $10$. What is the smallest integer greater than $500$ that is relatively prime to Grogg's favorite number?
Mathematics
1 answer:
soldi70 [24.7K]2 years ago
8 0

Product of the integers from $1$ to $10$ is $3628800$.

So, Grogg's favorite number is $3628800$.

The smallest integer greater than $500$ that is relatively prime to Grogg's favorite number should not have a common divisor with $3628800$.

This means, that number should not be divisible by any of the integers from $2$ to $10$.

Clearly, $503$ is the smallest integer greater than $500$ that is relatively prime to Grogg's favorite number.

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I tell you these facts about a mystery number, $c$: $\bullet$ $1.5 < c < 2$ $\bullet$ $c$ can be written as a fraction wit
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Answer:

Possible answer: \displaystyle c = \frac{16}{10} = \frac{8}{5} = 1.6.

Step-by-step explanation:

Rewrite the bounds of c as fractions:

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\displaystyle 2 = 2 \times 1 = 2 \times \frac{2}{2} = \frac{4}{2}.

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\displaystyle \frac{3}{2} < c < \frac{4}{2}.

If the denominator of c is also 2, then the range for its numerator (call it p) would be 3 < p < 4. Apparently, no whole number could fit into this interval. The reason is that the interval is open, and the difference between the bounds is less than 2.

To solve this problem, consider scaling up the denominator. To make sure that the numerator of the bounds are still whole numbers, multiply both the numerator and the denominator by a whole number (for example, 2.)

\displaystyle \frac{3}{2} = \frac{2 \times 3}{2 \times 2} = \frac{6}{4}.

\displaystyle \frac{4}{2} = \frac{2\times 4}{2 \times 2} = \frac{8}{4}.

At this point, the difference between the numerators is now 2. That allows a number (7 in this case) to fit between the bounds. However, \displaystyle \frac{1}{c} = \frac{4}{7} can't be written as finite decimals.

Try multiplying the numerator and the denominator by a different number.

\displaystyle \frac{3}{2} = \frac{3 \times 3}{3 \times 2} = \frac{9}{6}.

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\displaystyle \frac{3}{2} = \frac{4 \times 3}{4 \times 2} = \frac{12}{8}.

\displaystyle \frac{4}{2} = \frac{4\times 4}{4 \times 2} = \frac{16}{8}.

\displaystyle \frac{3}{2} = \frac{5 \times 3}{5 \times 2} = \frac{15}{10}.

\displaystyle \frac{4}{2} = \frac{5\times 4}{5 \times 2} = \frac{20}{10}.

It is important to note that some expressions for c can be simplified. For example, \displaystyle \frac{16}{10} = \frac{2 \times 8}{2 \times 5} = \frac{8}{5} because of the common factor 2.

Apparently \displaystyle c = \frac{16}{10} = \frac{8}{5} works. c = 1.6 while \displaystyle \frac{1}{c} = \frac{5}{8} = 0.625.

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