The center of mass is defined as a point on the straight line between two objects with masses m1 and m2 such that . What are the
2 answers:
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Answer:
In kJ/kg.K - 1.005 kJ/kg degrees Kalvin.
In J/g.°C - 1.005 J/g °C
In kcal/ kg °C 0.240 kcal/kg °C
In Btu/lbm-°F 0.240 Btu/lbm degree F
Step-by-step explanation:
given data:
specific heat of air = 1.005 kJ/kg °C
In kJ/kg.K
1.005 kJ./kg °C = 1.005 kJ/kg degrees Kelvin.
In J/g.°C
In kcal/ kg °C
For kJ/kg. °C to Btu/lbm-°F
Need to convert by taking following conversion ,From kJ to Btu, from kg to lbm and from degrees C to F.
1.005 kJ/kg C = 0.240 Btu/lbm degree F
Answer:
Step-by-step explanation:
Sample size = 95
X=cash carried by the persons
x bar = 8.00
s = sample std dev = 2.50
Std error =
Hence Z score would be
-0.00
b)
c) 95% conf interval margin of error = ±
=±0.54782
Confi interval = (8-0.5027, 8+0.5027)
= (7.4923, 8.5027)
C)If conf level increases, then width of interval would increase since critical value would increase.
If sample size increases std error would decrease and hence margin of error.
So interval would decrease.
Answer:
<h3>Q cuts the diagonal PA into 2 equal halves, since the diagonals of rhombus meet at right angles.</h3><h3>The value of x is 8.</h3>Step-by-step explanation:
Given that Quadrilateral CAMP below is a rhombus. the length PQ is (x+2) units, and the length of QA is (3x-14) units
From the given Q is the middle point, which cut the diagonal PA into 2 equal halves.
By the definition of rhombus, diagonals meet at right angles.
Implies that PQ = QA
x+2 = 3x - 14
x-3x=-14-2
-2x=-16
2x = 16
dividing by 2 on both sides, we will get,
The line segment
( since x=8)