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ludmilkaskok [199]

2 years ago

8

Mike has $25.00 to rent paddleboards for himself and a friend for 3 hours. Each paddleboard rental costs $3.75 per hour. Use the

drop-down menus to complete the statements below about the paddleboard rentals.

1 answer:

avanturin [10]2 years ago

4 0

<h3>It costs $ 22.5 for mike and his friend to rent paddle board for 3 hours</h3><h3>Mike has $ 2.5 remaining after rental</h3>

<em><u>Solution:</u></em>

Given that,

Mike has $25.00 to rent paddleboards for himself and a friend for 3 hours

Each paddleboard rental costs $3.75 per hour

So there are two persons = mike and his friend

1 hour = $ 3.75

Therefore, for 3 hours:

$3 \times 3.75 = 11.25$

<em><u>Thus for two person:</u></em>

11.25 + 11.25 = 22.5

Thus it costs $ 22.5 for mike and his friend to rent paddle board for 3 hours

Remaining amount = 25 - 22.5 = 2.5

Thus Mike has $ 2.5 remaining after rental

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1 year ago

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1 year ago

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Answer:

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$\sin(x+y)$ goes with $\frac{\sqrt{6}-\sqrt{2}}{4}$

$\tan(x+y)$ goes with $\sqrt{3}-2$

Step-by-step explanation:

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We are given:

$\sin(x)=\frac{\sqrt{2}}{2}$ which if we look at the unit circle we should see

$\cos(x)=\frac{\sqrt{2}}{2}$ .

We are also given:

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Apply both of these given to:

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$\cos(x)\cos(y)-\sin(x)\sin(y)$ by the addition identity for cosine.

$\frac{\sqrt{2}}{2}\frac{-1}{2}-\frac{\sqrt{2}}{2}\frac{\sqrt{3}}{2}$

$\frac{-\sqrt{2}}{4}-\frac{\sqrt{6}}{4}$

$\frac{-\sqrt{2}-\sqrt{6}}{4}$

$-\frac{\sqrt{6}+\sqrt{2}}{4}$

Apply both of the givens to:

$\sin(x+y)$

$\sin(x)\cos(y)+\sin(y)\cos(x)$ by addition identity for sine.

$\frac{\sqrt{2}}{2}\frac{-1}{2}+\frac{\sqrt{3}}{2}\frac{\sqrt{2}}{2}$

$\frac{-\sqrt{2}+\sqrt{6}}{4}$

$\frac{\sqrt{6}-\sqrt{2}}{4}$

Now I'm going to apply what 2 things we got previously to:

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$\frac{\sqrt{6}-\sqrt{2}}{-(\sqrt{6}+\sqrt{2})}$

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$-\frac{8-2\sqrt{12}}{4}$

There is a perfect square in 12, 4.

$-\frac{8-2\sqrt{4}\sqrt{3}}{4}$

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$-\frac{8-4\sqrt{3}}{4}$

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$-(2-\sqrt{3})$

Distribute:

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1 year ago