Mike has $25.00 to rent paddleboards for himself and a friend for 3 hours. Each paddleboard rental costs $3.75 per hour. Use the
1 answer:
<h3>It costs $ 22.5 for mike and his friend to rent paddle board for 3 hours</h3><h3>Mike has $ 2.5 remaining after rental</h3>
<em><u>Solution:</u></em>
Given that,
Mike has $25.00 to rent paddleboards for himself and a friend for 3 hours
Each paddleboard rental costs $3.75 per hour
So there are two persons = mike and his friend
1 hour = $ 3.75
Therefore, for 3 hours:
<em><u>Thus for two person:</u></em>
11.25 + 11.25 = 22.5
Thus it costs $ 22.5 for mike and his friend to rent paddle board for 3 hours
Remaining amount = 25 - 22.5 = 2.5
Thus Mike has $ 2.5 remaining after rental
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A logistic differential equation can be written as follows:
![\frac{dP}{dt} = rP[1- \frac{P}{K}]](https://tex.z-dn.net/?f=%20%5Cfrac%7BdP%7D%7Bdt%7D%20%3D%20rP%5B1-%20%5Cfrac%7BP%7D%7BK%7D%5D%20)
where r = growth parameter and K = carrying parameter.
In order to write you equation in this form, you have to regroup 2:
![\frac{dP}{dt} = 2P[1- \frac{P}{10000}]](https://tex.z-dn.net/?f=%20%5Cfrac%7BdP%7D%7Bdt%7D%20%3D%202P%5B1-%20%5Cfrac%7BP%7D%7B10000%7D%5D%20)
Therefore, in you case r = 2 and K = 10000
To solve the logistic differential equation you need to solve:
![\int { \frac{1}{[P(1- \frac{P}{K})] } } \, dP = \int {r} \, dt](https://tex.z-dn.net/?f=%20%5Cint%20%7B%20%5Cfrac%7B1%7D%7B%5BP%281-%20%5Cfrac%7BP%7D%7BK%7D%29%5D%20%7D%20%7D%20%5C%2C%20dP%20%3D%20%20%5Cint%20%7Br%7D%20%5C%2C%20dt%20%20)
The soution will be:
P(t) =
where P(0) is the initial population.
In your case, you'll have:
P(t) = <span>
Now you have to calculate the limit of P(t).
We know that
</span>
hence,
<span>
</span><span>
</span>
where r = growth parameter and K = carrying parameter.
In order to write you equation in this form, you have to regroup 2:
Therefore, in you case r = 2 and K = 10000
To solve the logistic differential equation you need to solve:
The soution will be:
P(t) =
where P(0) is the initial population.
In your case, you'll have:
P(t) = <span>
Now you have to calculate the limit of P(t).
We know that
</span>
hence,
</span><span>
</span>
Answer:
1). 0.903547
2). 0.275617
Step-by-step explanation:
It is given :
K people in a party with the following :
i). k = 5 with the probability of
ii). k = 10 with the probability of
iii). k = 10 with the probability
So the probability of at least two person out of the 'n' born people in same month is = 1 - P (none of the n born in the same month)
= 1 - P (choosing the n different months out of 365 days) =
1). Hence P(at least 2 born in the same month)=P(k=5 and at least 2 born in the same month)+P(k=10 and at least 2 born in the same month)+P(k=15 and at least 2 born in the same month)
=
=
= 0.903547
2).P( k = 10|at least 2 share their birthday in same month)
=P(k=10 and at least 2 born in the same month)/P(at least 2 share their birthday in same month)
=
= 0.0.275617
see the picture attached to better understand the problem
we know that
two tangent segments drawn from the same exterior point are congruent
so
JA=JB ,
LA=LC,
KC=KB
JA=13 units
LA=7 units
kC=10 units
hence
perimeter = JA+JB+LA+LC+KC+KB------> 13+13+7+7+10+10------> =60 units
therefore
the answer is
the perimeter of triangle JKL is 60 units
