It is given in the question that,
Line QS bisects angle PQR. Solve for x and find the measure of angle PQR.
And
Since QS bisects angle PQR, therefore
Substituting the values, we will get
Answer:
A Type II error is when the null hypothesis is failed to be rejected even when the alternative hypothesis is true.
In this case, it would represent that the new program really increases the pass rate, but the sample taken is not enough statistical evidence to prove it. Then, the null hypothesis is not rejected.
The consequence is that the new method would be discarded (or changed) eventhough it is a real improvement.
Step-by-step explanation:
Answer: C) For every original price, there is exactly one sale price.
For any function, we always have any input go to exactly one output. The original price is the input while the output is the sale price. If we had an original price of say $100, and two sale prices of $90 and $80, then the question would be "which is the true sale price?" and it would be ambiguous. This is one example of how useful it is to have one output for any input. The input in question must be in the domain.
As the table shows, we do not have any repeated original prices leading to different sale prices.
Answer:
Step-by-step explanation:
Let's assume this is a function
<u>The points are</u>
<u>Since it is linear relation, we'll get the slope intercept form</u>
- g = ms + b, where g- number of gallons, s- time in seconds, b- y intercept
<u>Using the points, let's calculate the formula</u>
- m = (10 - 13)/(60 - 40) = -3/20
- 10 = -3/20*60 + b
- 10 = - 9 + b
- b = 19
<u>So the formula is:</u>
In Δ ABC, ∠A=120°, AB=AC=1
To draw a circumscribed circle Draw perpendicular bisectors of any of two sides.The point where these bisectors meet is the center of the circle.Mark the center as O.
Then join OA, OB, and OC.
Taking any one OA,OB and OC as radius draw the circumcircle.
Now, from O Draw OM⊥AB and ON⊥AC.
As chord AB and AC are equal,So OM and ON will also be equal.
The reason being that equal chords are equidistant from the center.
AM=MB=1/2 and AN=NC=1/2 [ perpendicular from the center to the chord bisects the chord.]
In Δ OMA and ΔONA
OM=ON [proved above]
OA is common.
MA=NA=1/2 [proved above]
ΔOMA≅ ONA [SSS]
∴ ∠OAN =∠OAM=60° [ CPCT]
In Δ OAN
OA=1
∴ OA=OB=OC=1, which is the radius of given Circumscribed circle.
