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krek1111 [17]
2 years ago
11

Which expression can be used to find the price of a $400 telescope after a 32% markup? Select all that apply.

Mathematics
1 answer:
blagie [28]2 years ago
7 0
<h3>Option D</h3><h3>The expression can be used to find the price of a $400 telescope after a 32% markup is: 400 + 400 (0.32 )</h3>

<em><u>Solution:</u></em>

Given that,

Price of telescope = $ 400

Mark up = 32 %

To find: Cost after mark up

The formula used is:

<h3>Cost after mark up = Price of telescope + 32 % of Price of telescope</h3>

Therefore,

Cost after mark up = 400 + 32 % of 400

\text{Cost after mark up } = 400 + \frac{32}{100} \times 400\\\\\text{Cost after mark up } = 400 + 0.32 \times 400\\\\\text{Cost after mark up } = 400 + 128\\\\\text{Cost after mark up } = 528

Thus cost after mark up is $ 528 and expression is 400 + 400 (0.32 )

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The function is given by

y=45,200 + 1,900x

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Now when we compare we get m = 1,900 for our problem .

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2 years ago
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There are 53 students on the Jackson Middle School basketball teams. The number of 8th graders is 15 fewer than three times the
pshichka [43]

Answer:

The number of 7th students on the Jackson Middle School basketball teams is 17 and the number of 8th students on the Jackson Middle School basketball teams is 36

Step-by-step explanation:

Let

x ----> the number of 7th students on the Jackson Middle School basketball teams

y ----> the number of 8th students on the Jackson Middle School basketball teams

we know that

There are 53 students on the Jackson Middle School basketball teams

so

x+y=53 -----> equation A

The number of 8th graders is 15 fewer than three times the number of 7th graders

so

y=3x-15 ----> equation B

substitute equation B in equation A

x+(3x-15)=53

solve for x

x+3x=53+15\\4x=68\\x=17

Find the value of y

y=3(17)-15=36

therefore

The number of 7th students on the Jackson Middle School basketball teams is 17 and the number of 8th students on the Jackson Middle School basketball teams is 36

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2 years ago
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7 plus 3 first than plus 2 my strategy is to look at the easier thing to add than add the second one
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The random variable X is normally distributed with mean 82 and standard deviation 7.4. Find the value of q such that P(82 − q &l
mezya [45]
P(82 - q < x < 82 + q) = 0.44
P(x < 82 + q) - P(82 - q) = 0.44
P(z < (82 + q - 82)/7.4 - P(z < (82 - q - 82)/7.4) = 0.44
P(z < q/7.4) - P(z < -q/7.4) = 0.44
P(z < q/7.4) - (1 - P(z < q/7.4) = 0.44
P(z < q/7.4) - 1 + P(z < q/7.4) = 0.44
2P(z < q/7.4) - 1 = 0.44
2P(z < q/7.4) = 1.44
P(z < q/7.4) = 0.72
P(z < q/7.4) = P(z < 0.583)
q/7.4 = 0.583
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2 years ago
PART A: Marvin has a coupon the discount is the rental of a full-size car by $25 they decide to buy insurance for each day if th
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Answer:

i dont know about the other parts but part A is 19

Step-by-step explanation:

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