Answer:
Null Hypothesis: H_0: \mu_A =\mu _B or \mu_A -\mu _B=0
Alternate Hypothesis: H_1: \mu_A >\mu _B or \mu_A -\mu _B>0
Here to test Fertilizer A height is greater than Fertilizer B
Two Sample T Test:
t=\frac{X_1-X_2}{\sqrt{S_p^2(1/n_1+1/n_2)}}
Where S_p^2=\frac{(n_1-1)S_1^2+(n_2-1)S_2^2}{n_1+n_2-2}
S_p^2=\frac{(14)0.25^2+(12)0.2^2}{15+13-2}= 0.0521154
t=\frac{12.92-12.63}{\sqrt{0.0521154(1/15+1/13)}}= 3.3524
P value for Test Statistic of P(3.3524,26) = 0.0012
df = n1+n2-2 = 26
Critical value of P : t_{0.025,26}=2.05553
We can conclude that Test statistic is significant. Sufficient evidence to prove that we can Reject Null hypothesis and can say Fertilizer A is greater than Fertilizer B.
Answer:
Total charge = 8.50x + 25.50
Step-by-step explanation:
You multiply the hourly charge($8.50) by the number of hours(x) and add the rental fee($25.50)
Plug -8 in for x:
4(-8) + 5
solve:
-32 + 5
-27
Let S = the sophomores
Let R = the freshmen
Short Answer C
s + r = 1595 (1)
s + 15 = r (2)
Substitute for r from equation (2) into equation (1)
s + s + 15 = 1595 Combine like terms
2s + 15 = 1595 Subtract 15 from both sides
2s = 1595 - 15
2s = 1580 Divide by 2
s = 1580/2
s = 795 sophmores.
s + r = 1595
795 + r = 1595 Subtract 795 from both sides
r = 1594 - 795
r = 800 Freshmen
Answer C <<<<<<
1/10 the value of 237 means we must multiply 1/10 by 237
1/10 * 237 = 23.7
Hope this helps!
