Answer:
35 pounds of $8.00 tea and 15 pounds of $6.00 tea
Step-by-step explanation:
Let x represent the pounds of tea of the $8 kind. 8x would represent the total cost of that type of tea. We can also say 50 - x is the pounds of tea of the $6 kind, so 6(50 - x) is the total cost of that type of tea. 50 * 7.4 represents the total cost of all the tea, and the expression 8x + 6(50 -x) would also represent the same thing. We can write this as an equation,
8x + 6(50 -x) = 50 * 7.4
simplify,
8x + 300 - 6x = 370
2x + 300 = 370
and solve.
2x = 70
x = 35
This means there is 35 pounds of the $8 kind.
We can subtract that from 50 to find,
50 - 35 = 15,
15 pounds is the amount of the $6 kind.
-120 ÷ 15 = -8.
Hope this helps.
A=30000+0.03S and B=25000+0.05S.
When A=B, 5000=0.02S, so S=$250000 when the earnings are the same.
The slope of A is smaller than that of B. In excess of this value of S B pays more than A and below it A pays more than B.
So answer option B. (When S=0, clearly A is better than B. Put S=$300000, A pays $39000 and B pays $40000).
9514 1404 393
Answer:
(dN)/(dt) = (0.4)/(1200)N(1200-N) -50
142 fish
Step-by-step explanation:
A) The differential equation is modified by adding a -50 fish per year constant term:
(dN)/(dt) = (0.4)/(1200)N(1200-N) -50
__
B) The steady-state value of the fish population will be when N reaches the value that makes dN/dt = 0.
(0.4/1200)(N)(1200-N) -50 = 0
N(N-1200) = -(50)(1200)/0.4) . . . . rewrite so N^2 has a positive coefficient
N^2 -1200N + 600^2 = -150,000 +600^2 . . . . complete the square
(N -600)^2 = 210,000 . . . . . simplify
N = 600 + √210,000 ≈ 1058
This steady-state number of fish is ...
1200 - 1058 = 142 . . . . below the original carrying capacity
Answer:
$2680
Step-by-step explanation:
3.00-1.50= 1.50 profit per hotdog
1200+800=2000 expenses
1.50 (3120) = 4680
4680-2000=
2680 in profit
