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maw [93]
2 years ago
15

A street lamp casts a shadow 31.5 feet long, while an 8 foot-tall street sign casts a shadow of 14 feet long. What is the length

and height of the lamp?
Mathematics
1 answer:
sergeinik [125]2 years ago
4 0

Answer:

The answer to your question is the height of the lamp is 18.2 ft

Step-by-step explanation:

Data

Street lamp shadow = 31.5 ft

Street sign height = 8 ft

Street sign shadow = 14 ft

Street lamp height = x

Process

1.- To find the height of the lamp use proportions. In this kind of problem, we do not look for the length, but the shadow.

Street lamp height/street lamp shadow = street sign height/street sign

                                                                                                         shadow

Substitution

                                             x / 31.5 = 8 / 14

Solve for x

                                            x = (31.5)(8) / 14

Simplification

                                            x = 254.4 / 14

Result

                                            x = 18.2 ft              

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2 years ago
An ice cream stand uses the expression 2 + 0.5x2+0.5x2, plus, 0, point, 5, x to determine the cost (in dollars) of an ice cream
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Answer:

An ice cream cone with 5 scoops cost is, $4.5

Step-by-step explanation:

As per the statement:

An ice cream stand uses the expression 2+0.5x to determine the cost of an ice cream cone that has x scoops of ice cream.

⇒ Cost of an ice cream cone C(x) = 2+0.5x         .....[1]

Given: x = 5 scoops

We have to find the cost of an ice cream cone with 5 scoops cost.

Substitute the given value of x =5 in [1] we have;

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3 0
2 years ago
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Sarah kicked a ball in the air. The function
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Answer: The ball hits the ground at 5 s

Step-by-step explanation:

The question seems incomplete and there is not enough data. However, we can work with the following function to understand this problem:

f=30 t- 6t^{2} (1)

Where f models the height of the ball in meters and t the time.

Now, let's find the time t when the ball Sara kicked hits the ground (this is when f=0 m):

0=30 t- 6t^{2} (2)

Rearranging the equation:

6t^{2}-30 t=0 (3)

Dividing both sides of the equation by 6:

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This quadratic equation can be written in the form at^{2}+bt+c=0, and can be solved with the following formula:  

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Where:  

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Substituting the known values:  

t=\frac{-(-5) \pm \sqrt{(-5)^{2}-4(1)(0)}}{2(1)} (6)  

Solving we have the following result:

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2 years ago
Quadrilateral CAMP below is a rhombus. the length PQ is (x+2) units, and the length of QA is (3x-14) units. Which statements bes
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Answer:

<h3>Q cuts the diagonal PA into 2 equal halves, since the diagonals of rhombus meet at right angles.</h3><h3>The value of x is 8.</h3>

Step-by-step explanation:

Given that Quadrilateral CAMP below is a rhombus. the length PQ is (x+2) units, and the length of QA is (3x-14) units

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dividing by 2 on both sides, we will get,

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