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Dafna11 [192]
2 years ago
11

A poll shows that 60% of students enjoy mathematics. A random sample of 25 students showed that 80% of them enjoy mathematics. A

number generator was used to simulate 25 samples from a population in which 60% of students enjoy mathematics. The results are shown in the dot plot. What is the chance of getting a sample proportion of 80% or greater?
Mathematics
2 answers:
Allisa [31]2 years ago
6 0

Answer:

.40

Step-by-step explanation:

i took the test

Valentin [98]2 years ago
3 0

Answer:

50 chance

Step-by-step explanation:

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The regular octagon has a perimeter of 122.4 cm. A regular octagon with a radius of 20 centimeters and a perimeter of 122.4 cent
Mamont248 [21]

A C and E

Step-by-step explanation:

I took the test

6 0
2 years ago
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The vertices of rhombus defg are d(1, 4), e(4, 0), f(1, –4), and g(–2, 0). what is the perimeter of the rhombus?
Harman [31]

Answer: 20 unit.

Step-by-step explanation:

Since, Here the vertices of the rhombus defg are d(1, 4), e(4, 0), f(1, –4), and g(–2, 0).

Where, de, ef, fg, gd are sides of the rhombus defg.

By the distance formula,

de = \sqrt{(4-1)^2+(0-4)^2}

=\sqrt{3^2+4^2}

=\sqrt{9+16}

=\sqrt{25}

= 5

Thus, the side of rhombus = 5

By the property of rhombus,

de =  ef = fg = gd = 5 unit.

Thus, the perimeter of the given rhombus defg = de +  ef + fg + gd = 5+5+5+5 = 20 unit

6 0
2 years ago
Read 2 more answers
For the upcoming holiday season, Dorothy wants to mold 20 bars of chocolate into tiny pyramids. Each bar of chocolate contains 6
lorasvet [3.4K]

Answer:

A. 180

Step-by-step explanation:

20*6=120\ in^{3}\ of\ chocolate \\\\\frac{1*1*2}{3} =\frac{2}{3}\ in^{3}\ per\ pyramid\\\\\frac{120}{\frac{2}{3} }\ cubes\\\\\frac{120*3}{2}\ cubes\\\\\frac{360}{2}\ cubes\\\\180\ cubes

7 0
2 years ago
Jane is going to walk once around the edge of a rectangular park. The park is 300 yards long and 200 feet wide. How far will Jan
vova2212 [387]
Jane will walk 2200 feet 
4 0
2 years ago
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Two cross sections of a right hexagonal pyramid are obtained by cutting the pyramid with planes parallel to the hexagonal base.
Tanya [424]

Answer:

The larger cross section is 24 meters away from the apex.

Step-by-step explanation:

The cross section of a right hexagonal pyramid is a hexagon; therefore, let us first get some things clear about a hexagon.

The length of the side of the hexagon is equal to the radius of the circle that inscribes it.

The area is

A=\frac{3\sqrt{3} }{2} r^2

Where r is the radius of the inscribing circle (or the length of side of the hexagon).

Now we are given the areas of the two cross sections of the right hexagonal pyramid:A_1=216\:ft^2\: \:\:\:A_2=486\:ft^2

From these areas we find the radius of the hexagons:

r_1=\sqrt{\frac{2A_1}{3\sqrt{3} } } =\sqrt{\frac{2*216}{3\sqrt{3} } }=\boxed{9.12ft}

r_2=\sqrt{\frac{2A_2}{3\sqrt{3} } } =\sqrt{\frac{2*486}{3\sqrt{3} } }=\boxed{13.68ft}

Now when we look at the right hexagonal pyramid from the sides ( as shown in the figure attached ), we see that r_1 r_2 form similar triangles with length H

Therefore we have:

\frac{H-8}{r_1} =\frac{H}{r_2}

We put in the numerical values of r_1, r_2 and solve for H:

\boxed{H=\frac{8r_2}{r_2-r_1} =\frac{8*13.677}{13.68-9.12} =24\:feet.}

8 0
2 years ago
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