Answer:
t=45
Step-by-step explanation:
54=t+9
54-9=t
t=45
Answer:
V(x)=(x+9) * (x-4) * (x+6)
Step-by-step explanation:
A fish tank is normally in the shape of a rectangular prism. The volume of a rectangular prism can be calculated using the following formula
V = w * h * l
where w represents the width, h represents the heigh, l represents the length, and V represents the volume of the rectangular prism/fish tank. Therefore, we can use the function provided in the question and simply add 3 units to the length and 2 units to the width in order for it to work for our new fish tank.
V(x)=(x+9) * (x-4) * (x+6)
Answer:
k = - 14
Step-by-step explanation:
given that (x - 5) is a factor of the polynomial then x = 5 is a root and
x³ - x² + kx - 30 = 0 for x = 5, that is
5³ - 5² + 5k - 30 = 0
125 - 25 + 5k - 30 = 0
70 + 5k = 0 ( subtract 70 from both sides )
5k = - 70 ( divide both sides by 5 )
k = - 14
First, 123 - 55 = 68 which is how many boys voted. So, the ratio is 55:68
You do the implcit differentation, then solve for y' and check where this is defined.
In your case: Differentiate implicitly: 2xy + x²y' - y² - x*2yy' = 0
Solve for y': y'(x²-2xy) +2xy - y² = 0
y' = (2xy-y²) / (x²-2xy)
Check where defined: y' is not defined if the denominator becomes zero, i.e.
x² - 2xy = 0 x(x - 2y) = 0
This has formal solutions x=0 and y=x/2. Now we check whether these values are possible for the initially given definition of y:
0^2*y - 0*y^2 =? 4 0 =? 4
This is impossible, hence the function is not defined for 0, and we can disregard this.
x^2*(x/2) - x(x/2)^2 =? 4 x^3/2 - x^3/4 = 4 x^3/4 = 4 x^3=16 x^3 = 16 x = cubicroot(16)
This is a possible value for y, so we have a point where y is defined, but not y'.
The solution to all of it is hence D - { cubicroot(16) }, where D is the domain of y (which nobody has asked for in this example :-).
(Actually, the check whether 0 is in D is superfluous: If you write as solution D - { 0, cubicroot(16) }, this is also correct - only it so happens that 0 is not in D, so the set difference cannot take it out of there ...).
If someone asks for that D, you have to solve the definition for y and find that domain - I don't know of any [general] way to find the domain without solving for the explicit function).
