5d + 2(2 - d) = 3(1 + d) + 1
5d + 2(2) - 2(d) = 3(1) + 3(d) + 1
5d + 4 - 2d = 3 + 3d + 1
5d - 2d + 4 = 3d + 3 + 1
3d + 4 = 3d + 4
<u>-3d -3d </u>
4 = 4
d = 0
<h2>
Answer:</h2>
The area of the top surface of the washer is: 160.14 square mm.
<h2>
Step-by-step explanation:</h2>
The top of the surface is in the shape of a annulus with a outer radius of 10 mm and a inner radius of 7 mm ( since the diameter of the hole is: 14 mm and we know that the radius is half of the diameter)
Now, we know that the area of the annulus region is given by:
where R is the outer radius and r is the inner radius.
Here we have:
Hence, we have:
The answer is 0.
assuming by the dots that it includes tan80 +tan100 +tan120 +tan140 +tan160 in the equation.
9514 1404 393
Answer:
∛(2500π)√37 m² ≈ 120.911 m²
Step-by-step explanation:
If the height is 3 times the diameter, it is 6 times the radius. Then the volume is ...
V = 1/3πr²h
V = 1/3πr²(6r) = 2πr³
For a volume of 100 m³, the radius is ...
100 m³ = 2πr³
r = ∛(50/π) m
The lateral area of the cone is computed from the slant height. For this cone, the slant height is found using the Pythagorean theorem:
s² = r² +(6r)² = 37r²
s = r√37
Then the lateral area is ...
LA = πrs
LA = π(∛(50/π) m)(∛(50/π) m)√37
LA = ∛(2500π)√37 m² ≈ 120.911 m²
