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Y_Kistochka [10]
1 year ago
13

Mia’s work to find the slope of a trend line through the points (3, 10) and (35, 91) is shown below.

Mathematics
2 answers:
pochemuha1 year ago
5 0
For this case the first thing you should know is that by definition the slope of the line is given by:
 m = (y2-y1) / (x2-x1)
 Where we have two ordered pairs:
 P1 = (x1, y1)
 P2 = (x2, y2)
 We observe then that according to the formula, the error of mine was to invert the numerator with the denominator.
 Answer: 
 C: Mia switched the numerator and the denominator.
Mrrafil [7]1 year ago
5 0

Answer:

Answer:  

C: Mia switched the numerator and the denominator.

Step-by-step explanation:

just took the test

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The green turtle lays eggs that are approximately spherical with an average diameter of 4.5 centimeters. each turtle lays an ave
Art [367]
The average volume if these eggs will be found as follows:
Volume of one egg is:
V=4/3πr²
V=4/3×π×(4.5/2)^3
V=71.57 cm³
Given that the turtle lays on average 113 eggs, thus the total volume of eggs will be:
(113×71.57)
=8187.41~8187 cm³

4 0
1 year ago
A candy store sells caramels and milk chocolate by the pound the table below shows the total cost in dollars for a pound of each
MakcuM [25]

The cost of 1\frac{3}{4} pounds chocolate milk is $6.25 more than the cost of 1\frac{3}{4} pounds of Caramel.

Step-by-step explanation:

Given,

Cost of one pound of Caramels = $10.28

Cost of 1\frac{3}{4} pounds of Caramel = 10.28*1\frac{3}{4}

Cost of 1\frac{3}{4} pounds = 10.28*\frac{7}{4}=\frac{71.96}{4}= \$17.99

Cost of one pound of chocolate milk = $13.85

Cost of 1\frac{3}{4} pounds = 13.85*1\frac{3}{4}=13.85*\frac{7}{4}

Cost of 1\frac{3}{4} pounds = \frac{96.95}{4}=\$24.24

Difference = 24.24 - 17.99 = $6.25

The cost of 1\frac{3}{4} pounds chocolate milk is $6.25 more than the cost of 1\frac{3}{4} pounds of Caramel.

Keywords: difference, multiplication

Learn more about multiplication at:

  • brainly.com/question/10414011
  • brainly.com/question/10483199

#LearnwithBrainly

5 0
1 year ago
If f (x) = StartRoot 4 x + 9 EndRoot + 2, which inequality can be used to find the domain of f(x)? StartRoot 4 x EndRoot greater
maxonik [38]

Answer:

Step-by-step explanation:

"f (x) = StartRoot 4 x + 9 EndRoot + 2" should be written as

 

Note that √(4x + 9) is a variation of the basic function y = √x, whose domain is [0, ∞ ).

The domain of f(x) = √(4x + 9) + 2 is found by taking the "argument" 4x + 9 of √(4x + 9) and setting it equal to zero:

4x + 9 ≥ 0, or

4x ≥ -9, or

x ≥ -9/4

This is the domain of the given function f(x) = √(4x + 9) + 2.  So long as x is ≥ -9/4, the function f(x) will be defined.

6 0
1 year ago
Read 2 more answers
Assume that 12 people, including the husband and wife pair, apply for 4 sales positions. People are hired at random.
Iteru [2.4K]

brainly.com/question/5218999


The formula C(n, r)= \frac{n!}{r!(n-r)!}, where r! is 1*2*3*...r

is the formula which gives us the total number of ways of forming groups of r objects, out of n objects.

for example, given 10 objects, there are C(10,6) ways of forming groups of 6, out of the 10 objects.

-----------------------------------------------------------------------------------------------


Selecting 4 people out of 12 can be done in :

\displaystyle{C(12, 4)= \frac{12!}{4!8!}= \frac{12\cdot11\cdot10\cdot9\cdot8!}{4!8!}= \frac{12\cdot11\cdot10\cdot9}{4!}=11\cdot5\cdot9= 495       many ways.


All the possible groups of 4 people, where the husband and wife are included, can be done in C(10, 2) many ways, since we only calculate the possible choices of 2 out of 10 people, to complete the groups of 4.


\displaystyle{ C(10, 2)= \frac{10!}{2!8!}= \frac{10\cdot9}{2}=45


Thus, the 

probability that both the husband and wife are hired is 45/495=0.09


Part 2)

The probability that one is hired and the other is not = 

P(husband hired, wife not hired) + P(wife hired, husband not hired)

these 2 are clearly equal, so it is enough to calculate one.


Consider the case : husband hired, wife not hired.

assuming the husband is hired, we have to calculate the possible groups of 3 that can be formed from 11-1 (the wife)=10 people.

this is 

\displaystyle{ C(10, 3)= \frac{10!}{3!7!}= \frac{10 \cdot9 \cdot8}{3\cdot2}=10\cdot3\cdot4=120


thus, 


P(husband hired, wife not hired)=120/495=0.24


thus, 

The probability that one is hired and the other is not = 

P(husband hired, wife not hired) + P(wife hired, husband not hired) =

0.24+0.24=0.48



Answer:


A) 0.09


B) 0.48

4 0
2 years ago
A random sample of 144 observations produced a sample proportion of 0.4. An approximate 90% confidence interval for the populati
EleoNora [17]

Answer:

CI =(0.333, 0.480)

Step-by-step explanation:

The formula for calculating the confidence interval is expressed as shown;

CI = p±Z * √p(1-p)/n±0.5/n

Z is the z-score at 90% confidence

p is the sample proportion

n is the sample size

Given n = 144, p = 0.4 and z-score at 90%  CI = 1.645 (from z table)

Substituting this values;

CI = p ± 1.645*√0.4(1-0.4)/144 ±0.5/n

CI = 0.4 ± 1.645*√0.4(0.6)/144 ± 0.5/144

CI = 0.4 ±1.645 * √0.24/144 ± 0.00347

CI = 0.4 ±1.645 * 0.04087± 0.00347

CI = 0.4±0.06723±0.00347

CI =(0.333, 0.480)

7 0
2 years ago
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