Perhaps the easiest way to solve this problem is to convert 13 into a fraction that has the same denominator as 7 5/8.
Convert both to improper fractions:
7 5/8 turns into 61/8, and
13 turns into 104/8.
Then, subtract 61/8 from 104/8:
104/8-61/8=43/8.
Simplify (mixed fraction):
5 3/8.
The second ribbon has a length of 5 3/8 meters.
Hey!
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Let's Solve A:
1/2 = 0.5
0.5 + 0.30 = 0.80
a = 0.80
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Let's Solve B:
3/4 = 0.75
0.10 + 0.75 = 0.85
b = 0.85
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Let's Solve C:
1/3 ≈ 0.33
0.33 + 0.50 = 0.83
c = 0.83
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Let's Solve D:
1/3 ≈ 0.33
0.33 + 0.40 = 0.73
d = 0.73
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Answer:
By solving each equation we can see that option A has the lowest value!
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Hope This Helped! Good Luck!
For this case, what we are going to do first is to assume that all the exams are worth the same percentage of the final grade.
We have then that Lisa's average grade point equation is:

Where,
x: minimum note that lisa must obtain in the last exam.
Clearing x we have:
Answer:
the lowest grade she can get on her last test is:
x = 94
Answer:
A. y = 3sin(x-2) + 1
Step-by-step explanation:
Let us try reflecting (2,3) about x=y and across x-axis and y-axis.
If we are reflecting about y=x, that means both x,y values will be interchanged that is (2,3) will become (3,2)and this will be achieved by
.
And for reflection across x-axis,y-value will be multiplied by -1.That is (2,3) becomes (2,-3) and the matrix used to achieve it is
.
For reflection across y-axis, x-value will be multiplied by -1. That is (2,3) becomes (-2,3) when reflected across y-axis. The matrix used to achieve it will have -1 in the first place that is ![\left[\begin{array}{cc}-1&0\\0&1\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bcc%7D-1%260%5C%5C0%261%5Cend%7Barray%7D%5Cright%5D)