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telo118 [61]
1 year ago
15

Drag each expression to show whether it is equivalent to

Mathematics
1 answer:
Kazeer [188]1 year ago
7 0

Answer:

We need to find which expressions are equivalent to 6(c+6), 6c+6 or neither.

6c+12: We extract the greatest common factor which is 6. Remember, when we extract a GCM, we divide each term by it.

6c+12=+(c+2)

Therefore, this expression is equivalent to neither of the given expressions.

2(3c+3): We just need to apply the distributive property.

2(3c+3)=6c+6

Therefore, this expression is equivalen to 6c+6.

We use the same process to the other expressions.

(6c)+(6\times 6)=6c+36=6(c+6)

3c+6+3c=6c+6

6c+36=6(c+6)

(6+c)+(6+6)=c+18, equivalent to neither.

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Stores often mark up items each year to cover inflation. Last year, a CD at Juan’s Tunes cost $12.95. This year, the cost was ma
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Two cross sections of a right hexagonal pyramid are obtained by cutting the pyramid with planes parallel to the hexagonal base.
Tanya [424]

Answer:

The larger cross section is 24 meters away from the apex.

Step-by-step explanation:

The cross section of a right hexagonal pyramid is a hexagon; therefore, let us first get some things clear about a hexagon.

The length of the side of the hexagon is equal to the radius of the circle that inscribes it.

The area is

A=\frac{3\sqrt{3} }{2} r^2

Where r is the radius of the inscribing circle (or the length of side of the hexagon).

Now we are given the areas of the two cross sections of the right hexagonal pyramid:A_1=216\:ft^2\: \:\:\:A_2=486\:ft^2

From these areas we find the radius of the hexagons:

r_1=\sqrt{\frac{2A_1}{3\sqrt{3} } } =\sqrt{\frac{2*216}{3\sqrt{3} } }=\boxed{9.12ft}

r_2=\sqrt{\frac{2A_2}{3\sqrt{3} } } =\sqrt{\frac{2*486}{3\sqrt{3} } }=\boxed{13.68ft}

Now when we look at the right hexagonal pyramid from the sides ( as shown in the figure attached ), we see that r_1 r_2 form similar triangles with length H

Therefore we have:

\frac{H-8}{r_1} =\frac{H}{r_2}

We put in the numerical values of r_1, r_2 and solve for H:

\boxed{H=\frac{8r_2}{r_2-r_1} =\frac{8*13.677}{13.68-9.12} =24\:feet.}

8 0
2 years ago
A torch and a battery cost £2.50 altogether. The torch costs £2.00 more than the battery.
Genrish500 [490]

Answer:

\frac{1}{10}

Step-by-step explanation:

Let t represent the cost of the torch and b represent the cost of the battery.

The torch and a battery cost £2.50 altogether.

\Rightarrow t+b=2.50

The torch costs £2.00 more than the battery.

\Rightarrow t=b+2.00

We substitute the second equation into the first equation to get;

\Rightarrow b+2.00+b=2.50

\Rightarrow 2b=2.50-2.00

£2.50

\Rightarrow 2b=0.50

\Rightarrow b=0.25

The price of the battery is £0.25

We express this as a fraction of the total cost which is £2.50 to get;

\frac{0.25}{2.5}=\frac{1}{10}

8 0
2 years ago
HIJK is a parallelogram because the midpoint of both diagonals is ____ which means the diagonals bisect each other.
just olya [345]
ANSWER

The midpoint of both diagonals is

(1,0)
EXPLANATION

We can use either diagonals to determine the midpoint.

We use the midpoint formula

( \frac{x_1 + x_2}{2} , \frac{y_1 + y_2}{2} )

Let us use the first diagonals H(-2,2) and J(4,-2)

( \frac{ - 2 + 4}{2} , \frac{ - 2+ 2}{2} )

( \frac{ 2}{2} , \frac{ 0}{2} )

( 1, 0)

Using the second diagonals also gives,

( \frac{ - 2 + 4}{2} , \frac{ - 3+ 3}{2} )

( \frac{ 2}{2} , \frac{ 0}{2} )

( 1, 0)
4 0
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