First of all, a bit of theory: since the area of a square is given by

where s is the length of the square. So, if we invert this function we have
.
Moreover, the diagonal of a square cuts the square in two isosceles right triangles, whose legs are the sides, so the diagonal is the hypothenuse and it can be found by

So, the diagonal is the side length, multiplied by the square root of 2.
With that being said, your function could be something like this:
double diagonalFromArea(double area) {
double side = Math.sqrt(area);
double diagonal = side * Math.sqrt(2);
return diagonal;
}
Answer:
m = -2 and b = -1/3
m = -2 and b = -2/3.
Step-by-step explanation:
y = -2x - 1/3
y = -2x - 2/3
This system has no solutions because y cannot be 2 different values at once.
Y=70x
If she types at a consistent speed for 49 minutes she will have typed 3,430 words.
Given:
<span>12-foot wire is secured from the ground to the tree at a point 10 feet off the ground.
The tree meets the ground at a right angle.
When you visualize the scenario, the 12 foot wire would be the measure of the hypotenuse and the 10 feet off the ground will be the short leg or opposite. The long leg or adjacent is unknown.
We need to solve for sine theta because the value of hypotenuse and opposite is given.
sin </span>θ = opposite / hypotenuse
sin θ = 10 feet / 12 feet
sin θ = 0.833
θ = 0.83 / sin
θ = 56°
The wire would meet the ground at approximately 56° angle.