Answer:
The function of the graph is y = 3 cos (4x) ⇒ answer A
Step-by-step explanation:
- If the equation is y = A cos (B x)
* A is the amplitude
- The amplitude is the height from highest to lowest points and
divide the answer by 2
* The period is 2π/B
- The period is the distance from one peak to the next peak
* Lets look to the graph
- The maximum value is 3 and the minimum value is -3
∵ The height from the maximum point to the minimum point is
3 - (-3) = 3 + 3 = 6
∴ The amplitude is 6/2 = 3
∵ A is the amplitude
∴ A = 3
- The distance between two consecutive peaks is π/2
∵ The period is the distance from one peak to the next peak
∴ The period = π/2
∵ The period = 2π/B
∴ 2π/B = π/2 ⇒ divide both sides by π
∴ 2/B = 1/2 ⇒ by using cross multiplication
∴ B = 4
- Lets write the form of the function
∵ y = A cos (Bx)
∵ A = 3 and B = 4
∴ y = 3 cos (4x)
* The function of the graph is y = 3 cos (4x)
Answer:
0.875
Step-by-step explanation:
P(H=0) = 0.125
P(H=1) = 0.375
P(H=2) = 0.375
P(H=3) = 0.125
P(H<3) = P(H=0) + P(H=1) + P(H=2)
P(H<3) = 0.125 + 0.375 + 0.375
P(H<3) = 0.875
Answer:
"They are supplementary" ⇒ last answer
Step-by-step explanation:
* <em>Look to the attached figure</em>
- Two parallel horizontal lines are intersected by a third line
- The angles formed form intersection are labeled on the figure
- From the two parallel lines and
∠5 ≅ ∠1 ⇒ corresponding angles
m∠5 = m∠1
- A linear pair is two angles that are adjacent and form a line and
they are supplementary
∠1 and ∠3 form a line
∠1 and ∠3 are linear pair
* <em>lets prove that ∠3 and ∠5 are supplementary</em>
∵ m∠1 = m∠5 ⇒ corresponding angles
∵ ∠1 and ∠3 form a linear pair
∵ Linear pair are supplementary
∴ m∠1 + m∠3 = 180°
- By substitute ∠1 by ∠5
∴ m∠5 + m∠3 = 180
∴ ∠5 and ∠3 are supplementary
* The true statement is "They are supplementary"
Answer:
Step-by-step explanation:
Hello!
You have two random samples obtained from two different normal populations.
Sample 1
n₁= 15
X[bar]₁= 350
S₁= 12
Sample 2
n₂= 17
X[bar]₂= 342
S₂= 15
At α: 0.05 you need to obtain the p-value for testing variances for a one tailed test.
If the statistic hypotheses are:
H₀: σ₁² ≥ σ₂²
H₁: σ₁² < σ₂²
The statistic to test the variances ratio is the Stenecor's-F test.
~

The p-value is:
P(
≤0.64)= 0.02
I hope it helps!