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ioda
1 year ago
5

A plane that carries mail makes a round trip each day from Chicago to New York. It makes 3 intermediate stops on the way to New

York and 1 intermediate stop on the way back to Chicago. Suppose you make a graph of the altitude of the plane for one day, with time on the horizontal axis and altitude on the vertical axis. How many times will the graph touch the horizontal axis
Mathematics
2 answers:
coldgirl [10]1 year ago
6 0

If we assume that we're measuring altitude from ground level (as opposed to sea level), there will be x-axis touches for ...

  • Chicago (the starting point for the day)
  • stop 1
  • stop 2
  • stop 3
  • New York
  • stop 4
  • Chicago (the ending point for the day)

The graph will touch the horizontal axis 7 times.

Lelechka [254]1 year ago
6 0

Answer:

7 times the graph will touch the horizontal axis

Step-by-step explanation:

It flow from Chicago to first intermediate stop, Number of times on the horizontal axis 1.

1st intermediate stop to 2nd intermediate stop, Number of times on the horizontal axis 2.

2nd intermediate stop to 3rd intermediate stop, Number of times on the horizontal axis 3.

3rd intermediate stop to New York, Number of times on the horizontal axis 5.

Return

New York to 1st intermediate stop, Number of times on the horizontal axis 6.

1st intermediate stop to Chicago, Number of times on the horizontal axis 7.

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Answer:

The domain of the function is all real numbers (-\infty,\infty) and the range is all positive real numbers (0,\infty)

Step-by-step explanation:

We have the following function f(x)=(\frac{1}{5} )^x and we want to find the domain and the range.

The function we have is an example of an exponential function f(x)=b^x with b > 0 and b ≠ 1. This types of functions in general have the following properties:

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The domain of a function is the specific set of values that the independent variable in a function can take on.

When determining domain it is more convenient to determine where the function would not exist.

This function has no undefined points nor domain constraints. Therefore the domain is (-\infty,\infty).

The range is the resulting values that the dependent variable can have as x varies throughout the domain. Therefore the range is (0,\infty).

We can check our results with the graph of the function.

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Hi there! Osvoldo did not meet his goal.

(In my answering I suppose you mean 30%, 220 grams of carbohydrates and 55 grams of whole grains, if this is incorrect, please let me know)

Today Osvoldo ate 220 grams of carbohydrates.
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If at least 66 grams of Osvoldo's total consumption consisted of whole grains, he would have met his goal. However, he only ate 55 grams of whole grains (which is less than 66), and therefore he did not meet his goal.
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You deposit $300 in a savings account that pays 6% interest compounded semiannually. How much will you have at the middle of the
Makovka662 [10]

Answer:

  • The total amount accrued, principal plus interest,  from compound interest on an original principal of  $ 300.00 at a rate of 6% per year  compounded 2 times per year  over 0.5 years is $ 309.00.

  • The total amount accrued, principal plus interest,  from compound interest on an original principal of  $ 300.00 at a rate of 6% per year  compounded 2 times per year  over 1 year is $ 318.27.

Step-by-step explanation:

a)  How much will you have at the middle of the first year?

Using the formula

A\:=\:P\left(1+\frac{r}{n}\right)^{nt}

where

  • Principle = P
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  • A = Total amount

Given:

Principle P = $300

Annual rate r = 6% = 0.06 per year

Compound n = Semi-Annually = 2

Time (t in years) = 0.5 years

To determine:

Total amount = A = ?

Using the formula

A\:=\:P\left(1+\frac{r}{n}\right)^{nt}

substituting the values

A=300\left(1+\frac{0.06}{2}\right)^{\left(2\right)\left(0.5\right)}

A=300\cdot \frac{2.06}{2}

A=\frac{618}{2}

A=309 $

Therefore, the total amount accrued, principal plus interest,  from compound interest on an original principal of  $ 300.00 at a rate of 6% per year  compounded 2 times per year  over 0.5 years is $ 309.00.

Part b) How much at the end of one year?

Using the formula

A\:=\:P\left(1+\frac{r}{n}\right)^{nt}

where

  • Principle = P
  • Annual rate = r
  • Compound = n
  • Time  = (t in years)
  • A = Total amount

Given:

Principle P = $300

Annual rate r = 6% = 0.06 per year

Compound n = Semi-Annually = 2

Time (t in years) = 1 years

To determine:

Total amount = A = ?

so using the formula

A\:=\:P\left(1+\frac{r}{n}\right)^{nt}

so substituting the values

A\:=\:300\left(1+\frac{0.06}{2}\right)^{\left(2\right)\left(1\right)}

A=300\cdot \frac{2.06^2}{2^2}

A=318.27 $

Therefore, the total amount accrued, principal plus interest,  from compound interest on an original principal of  $ 300.00 at a rate of 6% per year  compounded 2 times per year  over 1 year is $ 318.27.

3 0
2 years ago
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