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Ivanshal [37]
2 years ago
9

Which equations are in standard form? Check all that apply y = 2x + 5 2x + 3y = –6 –4x + 3y = 12 y = y equals StartFraction 3 Ov

er 2 EndFraction x minus 9.x – 9 StartFraction one-half EndFraction x plus 3 equals 6.x + 3 = 6 x – y = 5 5x + 3y = 5 x plus 3 y equals StartFraction one-half EndFraction.
Mathematics
2 answers:
suter [353]2 years ago
8 0

Answer:

the answers are B. and F.

Step-by-step explanation:

AfilCa [17]2 years ago
3 0

Answer:

b,F

Step-by-step explanation:

i got it  lol

You might be interested in
I see that your new product is available for 412.50 on the website. How much is it if I buy it in the store? The website is a 25
OverLord2011 [107]

Answer with explanation:

Price of Product on the Website = $ 412.50

It is given that, product is offered at a discount of 25% on the website.

Let actual price of product on the store = $ x

Writing the above statement in terms of equation

→Price at store - Discount= Price at Website

x-\frac{25\times x}{100}=412.50\\\\ \frac{75 x}{100}=412.50\\\\x=\frac{41250}{75}\\\\x=550

Price at store of that Product = $ 550

3 0
2 years ago
Suppose that 20% of the adult women in the United States dye or highlight their hair. We would like to know the probability that
Rasek [7]

Answer:

71.08% probability that pˆ takes a value between 0.17 and 0.23.

Step-by-step explanation:

We use the binomial approxiation to the normal to solve this question.

Binomial probability distribution

Probability of exactly x sucesses on n repeated trials, with p probability.

Can be approximated to a normal distribution, using the expected value and the standard deviation.

The expected value of the binomial distribution is:

E(X) = np

The standard deviation of the binomial distribution is:

\sqrt{V(X)} = \sqrt{np(1-p)}

Normal probability distribution

Problems of normally distributed samples can be solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

When we are approximating a binomial distribution to a normal one, we have that \mu = E(X), \sigma = \sqrt{V(X)}.

In this problem, we have that:

p = 0.2, n = 200. So

\mu = E(X) = np = 200*0.2 = 40

\sigma = \sqrt{V(X)} = \sqrt{np(1-p)} = \sqrt{200*0.2*0.8} = 5.66

In other words, find probability that pˆ takes a value between 0.17 and 0.23.

This probability is the pvalue of Z when X = 200*0.23 = 46 subtracted by the pvalue of Z when X = 200*0.17 = 34. So

X = 46

Z = \frac{X - \mu}{\sigma}

Z = \frac{46 - 40}{5.66}

Z = 1.06

Z = 1.06 has a pvalue of 0.8554

X = 34

Z = \frac{X - \mu}{\sigma}

Z = \frac{34 - 40}{5.66}

Z = -1.06

Z = -1.06 has a pvalue of 0.1446

0.8554 - 0.1446 = 0.7108

71.08% probability that pˆ takes a value between 0.17 and 0.23.

6 0
2 years ago
Ray feeds his dog 0.12 kilogram of dry dog food each
Julli [10]

Answer:

The smallest bag that has enough food to feed his bag for one month

 = 3.6 kilogram

Step-by-step explanation:

The quantity of dry food Ray feeds his dog = 0.12 kilogram

So the quantity of food he feeds his dog in one month

    = 0.12 × 30              ∵ since 1 month = 30 days

    =  3.6 kilogram

The smallest bag that has enough food to feed his bag for one month

 = 3.6 kilogram

3 0
2 years ago
Which expression is equivalent to b^-2/ab^-3 assume a=0 b=0
andrey2020 [161]
B^-2/ab^-3 = b^-2/b^-3 x 1/a = b^[-2-(-3)] x 1/a = b x 1/a = b/a
3 0
1 year ago
Read 2 more answers
PATS, PETE AND KOFFI ANNUAL SALARIES AGGREGATE TO 200,000.00 A YEAR PETE MAKES $11000.00 MORE THAN KOFFI AND PAT MAKES $1000.00
grandymaker [24]

Answer:

Koffi's monthly salary: $3500 ($42000 annually)

Pete's monthly salary: $4416.7 ($53000 annually)

Pat's monthly salary: $8750 ($105000 annually)

Step-by-step explanation:

Let x represent Pat's annual salary

Let y represent Pete's annual salary

Let z represent Koffi's annual salary

According to the question, their annual salaries sum up to$200000 i.e. x + y + z= $200000

Pete makes $11000 more than Koffi anually means that y = $11000 + z

Pat makes $1000 less than twice (×2) of Pete's annual salary i.e. x = 2y - $1000

Hence, we have 3 equations:

(1)..... x + y + z= $200000

(2).... y = $11000 + z

(3).... x = 2y - $1000

First, we substitute y into equation (3) i.e.

x = 2(11000 + z) - 1000

x = 22000 + 2z - 1000

x = 21000 + 2z............ (4)

We then insert equations (4) and (2) into equation (1) to get z:

x + y + z = 200000

21000 + 2z + 11000 + z + z = 200000

4z + 32000 = 200000

4z = 200000 - 32000

4z = 168000

z = 42000

Hence, z (Koffi's) annual salary is $42000.

To get y, we substitute z in equation (2).

y = 11000 + z

y = 11000 + 42000

y = 53000

Hence, y (Pete's) annual salary is $53000

To get x, we add $42000 with $53000, and subtract from $200000 i.e. 42000 + 53000 = 95000

200000 - 95000 = 105000

Hence, x (Pat's) annual salary is $105000.

In order to get the monthly salary of each individual, we divide their annual salary by 12:

Koffi (z) = 42000/12 = $3500

Pete (y) = 53000/12 = $4416.7

Pat (x) = 105000/12 = $8750

4 0
1 year ago
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