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1 year ago

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Anna and Lionel share $675 in the ratio 4 : 5 Lionel gives 3/5 of his share of the money to his mother. How much money does Lion

el give to his mother?

1 answer:

Alika [10]1 year ago

7 0

Answer:

$225

Step-by-step explanation:

Total share ratio = 4+5 = 9

Lionel's ratio = 5

Lionel's share = (5/9) × 675

= $375

Lionel's mum = (3/5) x 375

= $225

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Stolb23 [73]

The annswer is y=log3x

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The number of flaws in a fiber optic cable follows a Poisson distribution. It is known that the mean number of flaws in 50m of c

boyakko [2]

Answer:

(a) The probability of exactly three flaws in 150 m of cable is 0.21246

(b) The probability of at least two flaws in 100m of cable is 0.69155

(c) The probability of exactly one flaw in the first 50 m of cable, and exactly one flaw in the second 50 m of cable is 0.13063

Step-by-step explanation:

A random variable X has a Poisson distribution and it is referred to as Poisson random variable if and only if its probability distribution is given by

$p(x;\lambda)=\frac{\lambda e^{-\lambda}}{x!}$ for x = 0, 1, 2, ...

where $\lambda$ , the mean number of successes.

(a) To find the probability of exactly three flaws in 150 m of cable, we first need to find the mean number of flaws in 150 m, we know that the mean number of flaws in 50 m of cable is 1.2, so the mean number of flaws in 150 m of cable is $1.2 \cdot 3 =3.6$

The probability of exactly three flaws in 150 m of cable is

$P(X=3)=p(3;3.6)=\frac{3.6^3e^{-3.6}}{3!} \approx 0.21246$

(b) The probability of at least two flaws in 100m of cable is,

we know that the mean number of flaws in 50 m of cable is 1.2, so the mean number of flaws in 100 m of cable is $1.2 \cdot 2 =2.4$

$P(X\geq 2)=1-P(X$

$P(X\geq 2)=1-p(0;2.4)-p(1;2.4)\\\\P(X\geq 2)=1-\frac{2.4^0e^{-2.4}}{0!}-\frac{2.4^1e^{-2.4}}{1!}\\\\P(X\geq 2)\approx 0.69155$

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$P(X=1)=p(1;1.2)=\frac{1.2^1e^{-1.2}}{1!}\\P(X=1)\approx 0.36143$

The occurrence of flaws in the first and second 50 m of cable are independent events. Therefore the probability of exactly one flaw in the first 50 m and exactly one flaw in the second 50 m is

$(0.36143)(0.36143) = 0.13063$

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2 years ago

A package of hamburgers contains 8 patties and costs $7.50. Part A.) Luna has to buy at least 16 packages for an upcoming picnic

Rus_ich [418]

Answer:

Part A) $p\geq 128\ patties$

Part B) She will spend more than $\$142.50$

Step-by-step explanation:

Let

p-----> the number of hamburger patties

Part A) Luna has to buy at least 16 packages for an upcoming picnic

$p\geq 16*8$

$p\geq 128\ patties$

Part B) Suppose she actually needs more than 150 hamburgers. How much will she spend?

Let

c---------> the total cost

step 1

Divide 150 hamburgers by 8 (a package of hamburgers)

so

$\frac{150}{8} =18.75\ package$

round to the nearest whole number

$18.75=19\ package$ ----> the minimum number of packages

step 2

$c>19*\$7.50$

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Let the distance of the first part of the race be x, and that of the second part, 15 - x, then
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Therefore, the distance of the first part of the race is 5 miles and the time is 5/8 = 0.625 hours or 37.5 minutes
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I believe it is C (p=140 s=40)

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