Answer:
4.79$ for each mug
Step-by-step explanation:
38.32/8 = 4.79 and to double-check do 4.79*8
Answer: We reject the null hypothesis, and we use Normal distribution for the test.
Step-by-step explanation:
Since we have given that
We claim that
Null hypothesis : 
Alternate hypothesis : 
There is 5% level of significance.

So, the test statistic would be

Since alternate hypothesis is left tailed test.
So, p-value = P(z≤-2.31)=0.0401
And the P-value =0.0401 is less than the given level of significance i.e. 5% 0.05.
So, we reject the null hypothesis, and we use Normal distribution for the test.
Answer:
Sofia will order 7 more rolls of sushi (84 pieces) and pay $56
Step-by-step explanation:
They need at least 100 pieces of sushi
Sofia had ordered and paid for 24 pieces of sushi already
Sushi comes in rolls
Each roll=12 pieces at $8
R=additional rolls that Sofia orders
Additional sushi= Needed sushi - ordered sushi
=100-24
=76 pieces of sushi
Each roll has 12 pieces
76/12=6.33
Sofia has to order in rolls
So, she will order 7 more rolls of sushi of 12 pieces each
12*7=84 pieces
Recall, that they needed at least 100 pieces, so the number of pieces could be more than 100
If Sofia orders 84 pieces + the already ordered 24 pieces
Total pieces=108 pieces
She has paid for 24 pieces (3 rolls) at $8 per roll
7 rolls=$8*7
=$56
Answer:
The herbicide has no impact on fish
Step-by-step explanation:
Experimental research includes to divide the concerned group 'fishes' here into 'treatment' & 'control' group, to study impact of a treatment. Hypothesis test the statistical significance of propositions. Null hypothesis signifies no impact, alternate hypothesis signifies impact.
Let averages enzyme level of treatment & control be Xt & Xc
- Null Hypothesis [H0] : Xt = Xc, or Xt - Xc = 0
- Alternate Hypothesis [H1] : Xt ≠ Xc, or Xt - Xc ≠ 0
If hypothesis test suggests that there is no significant difference between treatment & control group enzyme level, so we reject H0 & accept H1. It implies that the herbicide has no significant impact on fishes enzymes.