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1 year ago

60 PTS

1 answer:

3 0

A. It is an experiment as the sales director is applying treatment ( the training ) to a group and recording the results.

B. I would have 250 sales representatives from each region take the training and 250 from each region to not take it so i can be able to see if it affects both regions differently. The representatives from each region would be chosen at random and the length of their training would be the same for all.

C. now you would only be able to have 200 people from each region train. this would lower the percentage of the impact the training had on the amount of sales ( if any) . For example, if the original 250 trained people in a region increased the sales in that region by 20 percent and 50 of those people ended up not actually training, the sales would have only increased by 16 percent.

D. correlational research is best to establish causality. for example, the amount of training the representatives got may affect how much they are able to sell. also the number of representatives trained may affect the amount sold

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Zoe and Hannah share tips in the ratio 3:7. Last week, Zoe received £24. How much did Hannah receive last week?

Goshia [24]

Answer:

hannah gets £56

Step-by-step explanation:

z : h

3 : 7

24 : ?

24/3 = 8

8 x 7 = 56

£56

hope this helps

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8 0

1 year ago

PLEASE HELP ASAP: A particle is moving with velocity v(t) = t2 – 9t + 18 with distance, s measured in meters, left or right of z

dimaraw [331]

1) $\frac{v(8)-v(0)}{8 - 0} = \frac{10-18}{8} = -1\frac{m}{s}$ .
2) $v(5) = 5^2-9*5+18 = 25-45+18 = -2\frac{m}{s}$ .
3) The particle is moving right when the velocity function is positive: $0\ \textless \ t\ \textless \ 3$ or $6\ \textless \ t\ \textless \ 8$ .
4) When $0\ \textless \ t\ \textless \ \frac{9}{2}$ the particle is slowing down because the acceleration is close to zero $\Rightarrow$ the particle is speeding up when acceleration is increasing away from zero: $\frac{9}{2}\ \textless \ t\ \textless \ 8$ .
5) $(\frac{1}{8})* \int\limits^8_0 {t^2-9t+18dt}=\frac{1}{8}*(\frac{t^3}{3}-(\frac{9}{2}*t^2+18t)_{0}^{8}= \\=(\frac{1}{8})*(\frac{8^3}{3}-(\frac{9}{2})*8^2+18*8)=\frac{8^2}{3}-(\frac{9}{2})*8+18=3\frac{1}{3} \frac{m}{s}$ .

3 0

2 years ago

What is the true solution to In 20+In 5= 2 In x?<br><br>#31<br>

Neko [114]

Answer:

ln20+ln5=2lnx

ln(20x5)=lnx^2

ln100=1nx^2

100=x^2

square root

x=10

Hope This Helps!

5 0

2 years ago

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weeeeeb [17]

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1 year ago

In a group of 100 students, 25 own a laptop, 40 own a mobile phone, and 35 own either a

Talja [164]

Answer:

My best answer is that the probability is 35/100 that the student chosen at random owns neither a laptop nor a mobile phone.

Step-by-step explanation:

If you go back and read the introductory passage, you will notice it says, "In a group of 100 students... 35 own either a laptop or a mobile phone, but not both." And I think the other numbers, I.E. 25 and 40, were just meant to throw us off. Therefore, I think 35/100 is the probability.

8 0

1 year ago

**60 PTS**

60 PTS