All categories

2 years ago

60 PTS

1 answer:

3 0

A. It is an experiment as the sales director is applying treatment ( the training ) to a group and recording the results.

B. I would have 250 sales representatives from each region take the training and 250 from each region to not take it so i can be able to see if it affects both regions differently. The representatives from each region would be chosen at random and the length of their training would be the same for all.

C. now you would only be able to have 200 people from each region train. this would lower the percentage of the impact the training had on the amount of sales ( if any) . For example, if the original 250 trained people in a region increased the sales in that region by 20 percent and 50 of those people ended up not actually training, the sales would have only increased by 16 percent.

D. correlational research is best to establish causality. for example, the amount of training the representatives got may affect how much they are able to sell. also the number of representatives trained may affect the amount sold

You might be interested in

Of the 500 sample households in the previous exercise, 7 had three or more large-screen TVs. (a) The percentage of households in

likoan [24]

Answer:

a) The percentage of households in the town with three or more largescreen TVs is estimated as :

The best estimation for the population proportion is :

$\hat p=\frac{7}{500}=0.014$

And that represent the 1.4%.

b) And the 95% confidence interval would be given (0.00370;0.0243).

And the % would be between 0.37% and 2.43%.

Step-by-step explanation:

Data given and notation

n=500 represent the random sample taken

X=7 represent the households with three or more large-screen TVs

$\hat p=\frac{7}{500}=0.014$ estimated proportion of households with three or more large-screen TVs

$\alpha=0.05$ represent the significance level (no given, but is assumed)

z would represent the statistic (variable of interest)

p= population proportion of households with three or more large-screen TVs

Part a

The percentage of households in the town with three or more largescreen TVs is estimated as :

The best estimation for the population proportion is :

$\hat p=\frac{7}{500}=0.014$

And that represent the 1.4%.

Part b

Yes is possible. We hav that $np>10$ and $n(1-p)>10$ so we have the assumption of normality to find the interval.

The confidence interval would be given by this formula

$\hat p \pm z_{\alpha/2} \sqrt{\frac{\hat p(1-\hat p)}{n}}$

For the 95% confidence interval the value of $\alpha=1-0.95=0.05$ and $\alpha/2=0.025$ , with that value we can find the quantile required for the interval in the normal standard distribution.

$z_{\alpha/2}=1.96$

And replacing into the confidence interval formula we got:

$0.014 - 1.96 \sqrt{\frac{0.014(1-0.014)}{500}}=0.00370$

$0.014 + 1.96 \sqrt{\frac{0.014(1-0.014)}{500}}=0.0243$

And the 95% confidence interval would be given (0.00370;0.0243).

And the % would be between 0.37% and 2.43%.

4 0

2 years ago

A treasure map says that a treasure is buried so that it partitions the distance between a rock and a tree in a 5:9 ratio. Marin

djyliett [7]

Answer:

A) (7.6, 8.8)

which are the coordinates of the treasure.

Missing Problem Statement:

Given Options:

A) (11.4, 14.2)

B) (7.6, 8.8)

C) (5.7, 7.5)

D) (10.2, 12.6)

I have added the picture showing the traced map onto a coordinate plane to find exact location of treasure.

The coordinates of Tree are (16,21)

Coordinates of rock are (3,2)

Step-by-step explanation:

Let,

Coordinates of treasure be (a,b)

$d_{1}$ = distance from tree to treasure

$d_{2}$ =distance from rock to treasure

$d_{1}=\sqrt{(16-x)^2 + (21-y)^2}$

$d_{2}=\sqrt{x\2 + (y-2)^2}$

Given ratio between rock and tree, $\frac{d_{2}}{ d_{1}}=\frac{5}{9}$ = 0.55_______(Equation.1)

which will be used to locate the treasure.

Now we just need to cross check by putting the coordinates given in the options one by one to find out value of $d_{1}$ , $d_{2}$ and checking if it satisfies the Equation 1.

Check (A) (11.4, 14.2)

$d_{2}$ = 14.8, $d_{1}$ = 8.2,

$\frac{d_{2}}{ d_{1}}$ = 1.8

Check (C) (5.7, 7.5)

$d_{2}$ = 6.13, $d_{1}$ = 16.98,

$\frac{d_{2}}{ d_{1}}$ = 0.36

Check (D) (10.2, 12.6)

$d_{2}$ = 12.8, $d_{1}$ = 10.2,

$\frac{d_{2}}{ d_{1}}$ = 1.25

Check (B) (7.6, 8.8)

$d_{2}$ = 8.2, $d_{1}$ = 14.8,

$\frac{d_{2}}{ d_{1}}$ = 0.55

Which satisfies Equation 1, such that ratio between rock and tree is 5:9 or $\frac{d_{2}}{ d_{1}}=\frac{5}{9}$ = 0.55

So, the coordinates of the treasure are (B) (7.6, 8.8)

7 0

2 years ago

Read 2 more answers

A store sells yogurt in small, medium, and large sizes. A small yogurt costs $2, a medium costs $3, and a large costs $5. In one

lidiya [134]

Let S = number of small yogurts ($2 each).
Let M = number of medium yogurts ($3 each)
Let L = number of large yogurts ($5 each)

Total yogurts is 27, therefore
S + M + L = 27

Total revenue generated is $98, therefore
2S + 3M +5L = 98

There are five more large yogurts than small yogurts, therefore
L = S + 5, or
-S + L = 5

These three equations may be written as the matrix equation
[ 1 1 1 | |S| |27|
| 2 3 5 | |M| = |98|
| -1 0 1 | |L| | 5|

The determinant of the matrix is
D = 3 - (2+5) + 3 = -1.

Solve with Cramer's Rule to obtain
S = -[27*3) - (98-25) - 15]
= 7
M = -[(98-25) - 27(2+5) + (10+98)]
= 8
L = -[15 - (10+98) + 27(3)]
= 12

Answer: 7 small, 8 medium, 12 large yogurts.

8 0

2 years ago

PLEASE HELP! Robin bought a four-scoop ice cream cone having a scoop each of vanilla, chocolate, strawberry, and cherry. In how

soldi70 [24.7K]

There are 3 choices for the bottom scoop. Then there are only 3 choices for the scoop above that (since one flavor has already been used), then 2 choices for the next scoop, and 1 choice for the final scoop. This gives a total of 18 <span>possible cones.

Hope this helps.
</span>

4 0

2 years ago

Large flower pots weigh 28 pounds each.

LiRa [457]

Answer:

The correct answer is: 980 pounds

Step-by-step explanation:

1 flower pot = 28 pounds

1 crate = 35 pots

∴ 1 crate = 35 pots × 28 pounds = 980 pounds

5 0

2 years ago

Read 2 more answers

**60 PTS**

60 PTS