- The rate of the hose with the large diameter is:
Answer: A). 1/9.
- What is the unknown in the problem?
Answer: C). the time it takes for the hoses working together to fill the pool
-What part of the job does the hose with the large diameter do?
Answer: B). x/9
Answer:
x^2 -12x+20
Step-by-step explanation:
If the zeros of the functions are at 10 and 2
(x-10) (x-2)
FOIL
x^2 -2x-10x+20
Combine like terms
x^2 -12x+20
First identify what each variable means. since X is the amount of hours he works, and he makes $6.50 an hour, you know you need to multiply those two numbers together creating the 6.50x. You also know Y is his total sales, and he earns 4% of Y. To find 4% of Y you need to turn the percent into a decimal, and to do this you move the decimal two spaces to the left. Since 4 is a whole number, the decimal is after the 4 so you get .04 as your decimal. Then youd multiply .04 by Y getting .04y. Lastly you add 6.50x + .04y to get E, mikes total earnings. So your final equation is
6.50x + .04y = e
Hope this all makes sense