2010 47 +ten thousand split decide and
6. (5y+2)+14x=5y+(2+14x) (1point) A.associative property of addition B.associative property of multiplication C.commutative property of addition D.commutative property of multiplication 7. (m*n)*p=m*(n*p) (1 point) A. commutative property of addition B.commutative property of multiplication C.associative property of addition D. associative property of multiplication
Answer:
81%
Step-by-step explanation:
Let 'L' be the dominant and 'l' e the recessive allele for ‘lazybuttness’.
Since ‘lazybuttness’ is an autosomal dominant condition, the 19% of students affected by the condition correspond to the homozygous dominant (LL) and heterozygous (Ll) genotypes. Therefore, the rest of the population has the homozygous recessive genotype (ll) and is not affected. The frequency of students not affected is:
F = 100% - 19% = 81%
<h2> Heya </h2>
<h3>Selling Price = Rs. 851</h3>
<h3>Loss = 8%</h3>
<h3>FORMULA = 100/100 - LOSS % × SP</h3>
<h3>CP = 100/100 - 8 × 851</h3>
<h3> CP = 100/92 × 851</h3>
<h3> CP = Rs. 925</h3>
<h3>HOPE IT HELPS YOU.</h3>
