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ivann1987 [24]
2 years ago
9

Alissa is analyzing an exponential growth function that has been reflected across the y-axis. She states that the domain of the

reflected function will change because the input values will be the opposite sign from the reflected function. Simon disagrees with Alissa. He states that if an exponential function is reflected across the y-axis, the domain will still be all real numbers. Which student is correct and why?
A.Alissa is correct because the domain will change from negative to positive x-values.
B.Alissa is correct because a reflection across the y-axis will change the possible input values of the reflected function.
C.Simon is correct because even though the input values are opposite in the reflected function, any real number can be an input.
D.Neither student is correct.
Mathematics
2 answers:
storchak [24]2 years ago
6 0

i feel like u are going to delete this but if this helped please don't delete it the answer is, Simon is correct because even though the input values are opposite in the reflected function, any real number can be an input.

DanielleElmas [232]2 years ago
4 0

Answer:

C.Simon is correct because even though the input values are opposite in the reflected function, any real number can be an input.

Step-by-step explanation:

The domain of a function is all the values that can be put into the independant variable in order to value the dependant value, this basically means that the domain is all the values that you can give to the "x", and since you can put any value into the "x"the domain of that function is all the real numbers.

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g In a survey of 500 residents, 300 were opposed to the use of the photo-cop for issuing traffic tickets.The standard error of t
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Answer:

Z-score 1.96

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Hello!

The study variable in this case is

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To construct the Confidence interval, since the value of the population proportion is unknown, an estimated variance is used:

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I hope it helps!

7 0
2 years ago
For what value of "a" will the product shown below have a purely imaginary value? (Show work please)
MakcuM [25]
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2 years ago
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