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11111nata11111 [884]
2 years ago
6

Sal was tired of waiting for Amir to show up at their meeting place, so he started running at an average speed of 4.5 mph withou

t him. Ten minutes later, Amir still had 0.25 of a mile to go before he reached the meeting place, but Sal was 0.75 of a mile beyond it. If Amir is running at a faster pace, 6.7 mph, to the nearest hundredth of an hour, after how much time will Amir catch up to Sal?
0.04 hours
0.09 hours
0.23 hours
0.45 hours
Mathematics
1 answer:
arsen [322]2 years ago
4 0

The correct answer is 0.45 hours.

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Which inequality is represented by this graph? A number line going from negative 36 to negative 30. An open circle is at negativ
Montano1993 [528]

Answer:

-34.5≥ x

Step-by-step explanation:

  • Simply because the values start from -34.5 and then decrease
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(14.14) larry reads that 1 out of 6 eggs contains salmonella bacteria. so he never uses more than 5 eggs in cooking. if eggs do
melomori [17]

we know that

The probability that "at least one" is the probability of exactly one, exactly 2, exactly 3, 4 and 5 contain salmonella.

The easiest way to solve this is to recognise that "at least one" is ALL 100% of the possibilities EXCEPT that none have salmonella.

If the probability that any one egg has 1/6 chance of salmonella

then

the probability that any one egg will not have salmonella = 5/6.

Therefore

for all 5 to not have salmonella


= (5/6)^5 = 3125 / 7776

= 0.401877 = 0.40 to 2 decimal places


REMEMBER this is the probability that NONE have salmonella


Therefore

the probability that at least one does = 1 - 0.40

= 0.60


the answer is

0.60 or 60%

6 0
2 years ago
1. Walking to improve health. In a study investigating a link between walking and improved health (Social Science & Medicine
lora16 [44]

Answer:

a) We need to conduct a hypothesis in order to check if the true average number of days in the past month that adults walked for the purpose of health or recreation is lower than 5.5 days (a;ternative hypothesis) , the system of hypothesis would be:  

Null hypothesis:\mu \geq 5.5  

Alternative hypothesis:\mu < 5.5  

b) For this case since we want to determine if the true mean is lower than an specified value is a one tailed test

c) For this case the significance level is given \alpha=0.01 and we want to find the critical value, so we need to find a critical value on the normal standard distribution who accumulate 0.01 of the area on the right tail and if we use excel or a table we got:

z_{cric}= -2.326

And the rejection zone would be: (\infty ,-2.326)

And the region is on the figure attached

Step-by-step explanation:

Part a: State the null and alternative hypotheses.  

We need to conduct a hypothesis in order to check if the true average number of days in the past month that adults walked for the purpose of health or recreation is lower than 5.5 days (a;ternative hypothesis) , the system of hypothesis would be:  

Null hypothesis:\mu \geq 5.5  

Alternative hypothesis:\mu < 5.5  

Part b

For this case since we want to determine if the true mean is lower than an specified value is a one tailed test

Part c

For this case the significance level is given \alpha=0.01and we want to find the critical value, so we need to find a critical value on the normal standard distribution who accumulate 0.01 of the area on the right tail and if we use excel or a table we got:

z_{cric}= -2.326

And the rejection zone would be: (\infty ,-2.326)

And the region is on the figure attached

3 0
2 years ago
The mean GPA of student in a course at UCDevis is 3.2 with a standard deviation of 0.3. What percent of student in a course have
Orlov [11]

Answer:

81.86%

Step-by-step explanation:

We are given that the mean GPA of students in a course at UC Davis is 3.2 with a standard deviation of 0.3.

Assuming that the data follows normal distribution.

Let X = GPA of students in a course at UC Davis

So, X ~ Normal()

The z score probability distribution for normal distribution is given by;

                              Z  =   ~ N(0,1)

where,  = population mean GPA = 3.2

           = standard deviation = 0.3

Now, the probability that the students in the course have a GPA between 2.9 and 3.8 is given by = P(2.9 < X < 3.8)

       P(2.9 < X < 3.8) = P(X < 3.8) - P(X  2.9)

       P(X < 3.8) = P(  <  ) = P(Z < 2) = 0.97725

       P(X  2.9) = P(    ) = P(Z  -1) = 1 - P(Z < 1)

                                                        = 1 - 0.84134 = 0.15866

The above probability is calculated by looking at the value of x = 2 and x = 1 in the z table which has an area of 0.97725 and 0.84134 respectively.

Therefore, P(2.9 < X < 3.8) = 0.97725 - 0.15866 = 0.8186

Hence, 81.86% of students in the course have a GPA between 2.9 and 3.8.

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2 years ago
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Anarel [89]
She would've eaten half of the cake, or 8 oz.
4 0
2 years ago
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