A randomized study compared two different systems for tracking baggage at an airport. The treatment group using System A reporte
d a mean of 18.5 lost bags per day. The treatment group using System B reported a mean of 16.6 lost bags per day.
To determine if the results are significant, the data are re-randomized and the differences of the means are shown in the dot plot.
What is the best conclusion to make based on the data?
a) The difference of the means is not significant because the re-randomizations show that it is outside the range of what could happen by chance.
b) The difference of the means is significant because the re-randomizations show that it is within the range of what could happen by chance.
c) The difference of the means is significant because the re-randomizations show that it is outside the range of what could happen by chance.
d) The difference of the means is not significant because the re-randomizations show that it is within the range of what could happen by chance.
To determine if the results are significant, the data are re-randomized and the differences of the means are shown in the dot plot.
What is the best conclusion to make based on the data?
a) The difference of the means is not significant because the re-randomizations show that it is outside the range of what could happen by chance.
b) The difference of the means is significant because the re-randomizations show that it is within the range of what could happen by chance.
c) The difference of the means is significant because the re-randomizations show that it is outside the range of what could happen by chance.
d) The difference of the means is not significant because the re-randomizations show that it is within the range of what could happen by chance.
2 answers:
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Answer:
Probability that Adam and Ella will be selected:
Step-by-step explanation:
Probabilities
The probability of a random event E to occur is a real number between 0 and 1, both inclusive, where 0 indicates an impossible event and 1 a sure event. There are many techniques to compute probabilities depending on the particular situation and distribution.
This question will be solved by simple calculations and logic, given its simplicity. We know the middle school chess club has 5 members: Adam, Bradley, Carol, Dave, and Ella. Two of them are going to be selected at random to participate in the county chess tournament. We can calculate the number of different ways it can be done without any restriction. It's called the sample space.
The sample space of this event is the combination of 5 members regardless of their position. If {a,b,c,d,e} are the five members, then the possible combinations are {ab,ac,ad,ae,bc,bd,be,cd,ce,de}. Notice that there are only 10 possibilities because the combination ab is the same as ba since it's the same team for the tournament.
We can see there is only one combination of two specific letters out of 10. If a=Adam and e=Ella, only one combination is ae, the other 9 don't include both members, so the probability is