A = 1/2(8+4)(3)
A = 6 * 3
A = 18
answer
<span>18 square yards</span>
Total points is 23
<u>Explanation:</u>
Given:
Total number of baskets = 18
Let the number of 2 pointer shots be x
Let the number of 3 pointer shots be y
According to the question:
-1
The equation can be formed as:

On solving this equation further we get:

Putting the value of x = 4 in equation 1

Points for 2 pointer shots = 4 X 2
= 8
Points for 3 pointer shots = 5 X 3
= 15
Total points = 8 + 15
= 23
Therefore, total points is 23
Answer:
![4x^5\sqrt[3]{3x}](https://tex.z-dn.net/?f=%204x%5E5%5Csqrt%5B3%5D%7B3x%7D%20)
Step-by-step explanation:
I'm not sure I understand the problem, but I think it's this:
![\sqrt[3]{16x^7} \times \sqrt[3]{12x^9} =](https://tex.z-dn.net/?f=%20%5Csqrt%5B3%5D%7B16x%5E7%7D%20%5Ctimes%20%5Csqrt%5B3%5D%7B12x%5E9%7D%20%3D%20)
![= \sqrt[3]{16 \times 12 \times x^{16}}](https://tex.z-dn.net/?f=%3D%20%5Csqrt%5B3%5D%7B16%20%5Ctimes%2012%20%5Ctimes%20x%5E%7B16%7D%7D)
![= \sqrt[3]{192 \times x^{15} \times x}](https://tex.z-dn.net/?f=%3D%20%5Csqrt%5B3%5D%7B192%20%5Ctimes%20x%5E%7B15%7D%20%5Ctimes%20x%7D)
![= \sqrt[3]{64 \times 3 \times (x^5)^3 \times x}](https://tex.z-dn.net/?f=%20%3D%20%5Csqrt%5B3%5D%7B64%20%5Ctimes%203%20%5Ctimes%20%28x%5E5%29%5E3%20%5Ctimes%20x%7D%20)
![= \sqrt[3]{4^3 \times 3 \times (x^5)^3 \times x}](https://tex.z-dn.net/?f=%20%3D%20%5Csqrt%5B3%5D%7B4%5E3%20%5Ctimes%203%20%5Ctimes%20%28x%5E5%29%5E3%20%5Ctimes%20x%7D%20)
![= 4x^5\sqrt[3]{3x}](https://tex.z-dn.net/?f=%20%3D%204x%5E5%5Csqrt%5B3%5D%7B3x%7D%20)
<span>If Mary earns 7$ an hour, we need to multiplicate 7$ by the number of hours worked for the entire week so we can get the salary per week. And when we want to know how many hours she had worked, we have to "transform" the equation :
Salary per week = salary per hours x worked hours
Here, we know to informations : salary per hours and salary per week.
Worked hours = salary per week / salary per day
Worked hours = 143.50 / 7
Worked hours = 20.5
The greatest number of hours thats he works is 20h30.</span>